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lozanna [386]
3 years ago
7

Determine the measures of the angles of AMNO if the measures of the angles are in the ratio 2:4:6.

Mathematics
1 answer:
masha68 [24]3 years ago
8 0

Answer:

60,120,180

Step-by-step explanation:

360:(2+4+6)=30

30×2=60

30×4=120

30×6=180

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I need help with this question
sasho [114]

a+b= 8+24=32

Ab=8 x 24= 192

B/a= 24:8=3

(a+b)²=(8+24)² =64+576+384= 1024

Pls mark as brainliest

7 0
3 years ago
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Ming took a cab across town. His fare was \$22$22, and he leaves an 18\%18% tip. What is the total amount Ming pays the cab driv
Lilit [14]

Answer:

$25.96

Step-by-step explanation:

First, you turn the percent into a decimal, which gives you .18.  Then, you multiply $22 by .18.  Finally, you add the $3.96 that you get by multiplying $22 by .18, and you get the answer that is above.  Plz mark brainliest if correct.

6 0
3 years ago
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Can someone explain how to get the answer for the following question ?
zhenek [66]
The answer to the question is 1-5
3 0
2 years ago
Due SOON!!
DedPeter [7]

Answer:

?=19

x=30

Step-by-step explanation:

5/6x - 1/5x = 19

5(5/6x) - 6(1/5x) = 19

25/30x-6/30x=19

19/30x=19

19x=19(30)

19x=570

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6 0
3 years ago
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Ratling [72]

Answer:

Choice number one:

\displaystyle \frac{5}{10}\cdot \frac{4}{9}.

Step-by-step explanation:

  • Let A be the event that the number on the first card is even.
  • Let B be the event that the number on the second card is even.

The question is asking for the possibility that event A and B happen at the same time. However, whether A occurs or not will influence the probability of B. In other words, A and B are not independent. The probability that both A and B occur needs to be found as the product of

  • the probability that event A occurs, and
  • the probability that event B occurs given that event A occurs.

5 out of the ten numbers are even. The probability that event A occurs is:

\displaystyle P(A) = \frac{5}{10}.

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

\displaystyle P(B|A) = \frac{4}{9}.

The probability that both A and B occurs will be:

\displaystyle P(A \cap B) = P(B\cap A) =  P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}.

6 0
3 years ago
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