Answer:
Total Cost, C=$(16S +56)
Step-by-step explanation:
Chris buys 8 more Ninja Turtles than Star Wars action figures.
Cost of each Ninja Turtle = $7
Cost of each Star Wars = $9
Let number of Star Wars bought = S
As per question statement, number of Ninja Turtles bought = S+8
Cost of 'S' number of Star Wars = Number of Star Wars bought 
cost of each Star Wars
Total cost of Star Wars bought = S 9 or $9S
Similarly, Cost of 'S+8' number of Ninja Turtles = Number of Ninja Turtles bought cost of each Ninja Turtles
Total cost of Ninja Turtles bought = (S+8) 7 or $(7S +56)
Total Cost of the purchase = Total cost of Star Wars Bought + Total cost of Ninja Turtles bought
Total Cost of the purchase, C = 9S + (7S +56)
Answer:
m= -3/2
Step-by-step explanation:
Answer:
<u>x = 60°</u>
Step-by-step explanation:
The rest of the question is the attached figure.
And it is required to find the angle x.
As shown, a rhombus inside a regular hexagon.
The regular hexagon have 6 congruent angles, and the sum of the interior angles is 720°
So, the measure of one angle of the regular hexagon = 720/6 = 120°
The rhombus have 2 obtuse angles and 2 acute angles.
one of the obtuse angles of the rhombus is the same angle of the regular hexagon.
So, the measure of each acute angle of the rhombus = 180 - 120 = 60°
So, the measure of each acute angle of the rhombus + the measure of angle x = the measure of one angle of the regular hexagon.
So,
60 + x = 120
x = 120 - 60 = 60°
<u>So, the measure of the angle x = 60°</u>
Answer:
y = (11x + 13)e^(-4x-4)
Step-by-step explanation:
Given y'' + 8y' + 16 = 0
The auxiliary equation to the differential equation is:
m² + 8m + 16 = 0
Factorizing this, we have
(m + 4)² = 0
m = -4 twice
The complimentary solution is
y_c = (C1 + C2x)e^(-4x)
Using the initial conditions
y(-1) = 2
2 = (C1 -C2) e^4
C1 - C2 = 2e^(-4).................................(1)
y'(-1) = 3
y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)
3 = -4(C1 - C2)e^4 + C2e^4
-4C1 + 5C2 = 3e^(-4)..............................(2)
Solving (1) and (2) simultaneously, we have
From (1)
C1 = 2e^(-4) + C2
Using this in (2)
-4[2e^(-4) + C2] + 5C2 = 3e^(-4)
C2 = 11e^(-4)
C1 = 2e^(-4) + 11e^(-4)
= 13e^(-4)
The general solution is now
y = [13e^(-4) + 11xe^(-4)]e^(-4x)
= (11x + 13)e^(-4x-4)
Answer:
121
Step-by-step explanation:
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