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Mila [183]
3 years ago
11

Susan is buying black and green olives from the Olive bar for her party. She buys 4 pounds of olives. Black olives cost three do

llars a pound. Green olives cost five dollars a pound. She spends $15.50. How many pounds of each type of olives does she buy? Write and solve a system of equations. Give the answer to in context of the problem.
Mathematics
1 answer:
Papessa [141]3 years ago
4 0

Answer:

She buy <u>0.5 pounds</u> of black olives and <u>3.5 pounds</u> of green olives.

Step-by-step explanation:

Given:

Susan is buying black and green olives from the Olive bar for her party. She buys 4 pounds of olives.

Black olives cost three dollars a pound. Green olives cost five dollars a pound.

She spends $15.50.

Now, to find the pounds of olives she buy.

Let the pounds of black olives be x.

And the pounds of green olives be y.

So, total pounds of olives:

x+y=4

x=4-y    ........( 1 )

As, given the cost of black olives $3 a pound.

And cost of green olives $4 a pound.

Now, the total money spends:

3x+4y=15.50

Substituting the value of x from equation (1) we get:

3(4-y)+4y=15.50

12-3y+4y=15.50

12+y=15.50

<em>Subtracting both sides by 12 we get:</em>

y=3.5

<u>The green olives = 3.5 pounds.</u>

Now, substituting the value of y in equation (1):

x=4-y\\x=4-3.5\\x=0.5\ pounds.

<u>The black olives = 0.5 pounds.</u>

Therefore, she buy 0.5 pounds of black olives and 3.5 pounds of green olives.

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3 years ago
Evaluate the Riemann sum for f(x) = 3 - 1/2 times x between 2 and 14 where the endpoints are included with six subintervals taki
Digiron [165]

Answer:

-6

Step-by-step explanation:

Given that :

we are to evaluate the Riemann sum for f(x) = 3 - \dfrac{1}{2}x from 2 ≤ x ≤ 14

where the endpoints are included with six subintervals, taking the sample points to be the left endpoints.

The Riemann sum can be computed as follows:

L_6 = \int ^{14}_{2}3- \dfrac{1}{2}x \dx = \lim_{n \to \infty} \sum \limits ^6 _{i=1} \ f (x_i -1) \Delta x

where:

\Delta x = \dfrac{b-a}{a}

a = 2

b =14

n = 6

∴

\Delta x = \dfrac{14-2}{6}

\Delta x = \dfrac{12}{6}

\Delta x =2

Hence;

x_0 = 2 \\ \\  x_1 = 2+2 =4\\ \\  x_2 = 2 + 2(2) \\ \\  x_i = 2 + 2i

Here, we are  using left end-points, then:

x_i-1 = 2+ 2(i-1)

Replacing it into Riemann equation;

L_6 =  \lim_{n \to \infty}  \sum \imits ^{6}_{i=1} \begin {pmatrix}3 - \dfrac{1}{2} \begin {pmatrix}  2+2 (i-1)  \end {pmatrix} \end {pmatrix}2

L_6 =  \lim_{n \to \infty}  \sum \imits ^{6}_{i=1} 6 - (2+2(i-1))

L_6 =  \lim_{n \to \infty}  \sum \imits ^{6}_{i=1} 6 - (2+2i-2)

L_6 =  \lim_{n \to \infty}  \sum \imits ^{6}_{i=1} 6 -2i

L_6 =  \lim_{n \to \infty}  \sum \imits ^{6}_{i=1} 6 -   \lim_{n \to \infty}  \sum \imits ^{6}_{i=1} 2i

L_6 =  \lim_{n \to \infty}  \sum \imits ^{6}_{i=1} 6 - 2  \lim_{n \to \infty}  \sum \imits ^{6}_{i=1} i

Estimating the integrals, we have :

= 6n - 2 ( \dfrac{n(n-1)}{2})

= 6n - n(n+1)

replacing thevalue of n = 6 (i.e the sub interval number), we have:

= 6(6) - 6(6+1)

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= -6

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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Rudiy27
I hope this helps you




Area=length ×width



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Step-by-step explanation:

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