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2 years ago

How Many hundredths are in five tenths ..⬅️ ,how many thousandths are in five hundredths .¿

Mathematics

1 answer:

anzhelika [568]2 years ago

5 0

There are 0 hundredths in five tenths,
there is five thousandths in five hundredths.

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Geometry question for homework.

mars1129 [50]

So remember that the distance formula is $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

$\sqrt{(4-4)^2+(-2-(-5))^2}\\ \sqrt{0^2+3^2}\\ \sqrt{0+9}\\ \sqrt{9}\\ 3$

Distance between (4,-5) and (4,-2) is 3 units.

$\sqrt{(1-(-1))^2+(1-4)^2}\\ \sqrt{2^2+(-3)^2}\\ \sqrt{4+9}\\ \sqrt{13}$

Distance between (1,1) and (-1,4) is √13 (or 3.61 rounded to the hundreths) units.

3 0

2 years ago

Enoch is two times as old as MARTIN.three years ago,the difference between their ages was fifteen years.find their present ages

olga2289 [7]

9514 1404 393

Answer:

Enoch is 30
Martin is 15

Step-by-step explanation:

The difference in ages remains the same over time. Enoch, at twice Martin's age, is still 15 years older. That means Martin is 15 and Enoch is 30.

5 0

2 years ago

Data consistent with summary quantities in the article "Effects of Fast-Food Consumption on Energy Intake and Diet Quality Among

Olegator [25]

Answer:

a) X[bar]₁= 1839.20 cal

b) X[bar]₂= 1779.07 cal

c) S₁= 386.35 cal

Step-by-step explanation:

Hello!

You have two independent samples,

Sample 1: n₁= 15 children that did not eat fast food.

Sample 2: n₂= 15 children that ate fast food.

The study variables are:

X₁: Calorie consumption of a kid that does not eat fast food in one day.

X₂: Calorie consumprion of a kid that eats fast food in one day.

The point estimate of the population mean is the sample mean

X[bar]₁= (∑X₁/n₁) = (27588/15)= 1839.20 cal

X[bar]₂= (∑X₂/n₂)= (26686/15)= 1779.07 cal

To calculate the sample standard deiation, you have to calculate the sample variance first:

S₁²= $\frac{1}{n_1-1}$ [∑X₁² - (( ∑X₁)²/n₁)]= $\frac{1}{14} + [52829538 - (\frac{27588^{2} }{15})$ = 149263.4571 cal²

S₁= 386.35 cal

I hope it helps!

7 0

2 years ago

HELP ME PLEASE !!!!!!!!

andre [41]

Answer:

3 is yes, the rest is no

Step-by-step explanation:

for y = -6x - 9

(1) if x = 7, y = -51 => No

(2) if x = 3, y = -27 => No

(3) if x = -8, y = 39 => Yes

(4) if x = -5, y = 21 => No

8 0

1 year ago

Anyone know the answer??

Serggg [28]

Answer:

the second option

Step-by-step explanation:

in ax²+bx+c = 0:

$x = \frac{-b+-\sqrt{b^2-4ac} }{2a}$

subtract both sides by 6 to get to this form, as the right side will be left with 0

6x² + 8x - 6 = 0

here, the coefficient for x² (a) is 6, the coefficient for x (b) is 8, and the remaining number added on (c) is -6

plugging our numbers into the formula, we get

$x = \frac{-8+-\sqrt{(-8)^2-4(6)(-6)} }{2(6)}\\= \frac{-8+-\sqrt{64-(-144)} }{12} \\= \frac{-8+-\sqrt{208} }{12} \\ = \frac{-8+\sqrt{208} }{12} or \frac{-8-\sqrt{208} }{12}\\= 0.53518375848 or -1.86851709182\\= approximately -1.87, 0.54$

8 0

1 year ago