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babunello [35]
2 years ago
12

Solve the system of equation with substitution. y=4x+8 y=2x-9

Mathematics
1 answer:
Firlakuza [10]2 years ago
8 0
I actually just learned this. I think this is the right answer.

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makayla has $8 to buy at a school fair each ticket cost $1.50 which inequality best represents how many tickets she can buy
ivolga24 [154]

Answer:

Step-by-step explanation:

If she only has $8, she can't spend more than that.  In other words, she can spend ≤$8.

If each ticket is $1.50 per ticket, the inequality that represents how many tickets she can buy if x represents the number of tickets, is

1.5x ≤ 8

6 0
3 years ago
Okay so I think I got it right, I just need someone to check over it.
Paladinen [302]

Answer:

yes

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the value of x. Round to the nearest tenth.
serg [7]

Answer:

Where is the equation?

Step-by-step explanation:

8 0
3 years ago
Martha needs 28 strawberries for every 4 smoothies she makes. Complete the table using equivalent ratios.
S_A_V [24]

answer: 28: 4

21: 3

70: 10

step-by-step explanation:

divide 28 by 4, and of course, do to the bottom what you do to the top. 4 divided by 4 is 1, and 28 divided by 4 is 7.

7: 4.

then, multiply by the number of smoothies.

for 3, it's 21: 3.

for 10, it's 70: 10.

5 0
2 years ago
Calculating area of rectangle
PSYCHO15rus [73]

Answer:

Area = 216.108cm^2 --- You

Area = 216.940cm^2 --- Another student

Reason: Because there is a variation in the given dimensions

Step-by-step explanation:

Given

Your measurement

Length = 20.70cm; Width =10.44cm

Another students'

Length = 20.74cm; Width =10.46cm

Solving (a): The area

Area is calculated as:

Area = Length * Width

For you

Area = 20.70cm * 10.44cm

Area = 216.108cm^2

For the other student

Area = 20.74cm * 10.46cm

Area = 216.940cm^2

Solving (b): Reason for the variation in the areas

The given measurements are estimates of the dimensions of the rectangle.

Since there is a variation in the estimates, there will be some level of variation in the calculated area.

4 0
3 years ago
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