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dexar [7]
4 years ago
15

What ozone layer do we live in

Chemistry
1 answer:
daser333 [38]4 years ago
7 0
What ozone layer do we live in?

  Answer: We live in the troposphere. There are 4 ozone layers: Troposphere, Stratosphere, mesosphere and atmosphere(of course)
The troposphere is the first layer<span> above the surface and contains half of the </span>Earth's atmosphere<span>. Weather occurs in this </span><span>lay</span>
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Screenshot very easy
SpyIntel [72]

Answer:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶

Explanation:

Iron is soft, bright white metal.

Its symbol is Fe, atomic number is 26 and atomic mass is 55.85 amu.

It is present in group 8 of periodic table.

It is used to make the steel.

It is malleable and ductile used to make the sheets.

It is good conductor of heat and electricity because of moveable electrons that can easily move from one to another atom.

Its density is 7.87 g/cm³.

Electronic configuration:

Fe₂₃ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶

Abbreviated electronic configuration:

Fe₂₃ = [Ar] 3d⁶4s²

8 0
3 years ago
Read 2 more answers
Type the correct answer in the box. Express your answer to three significant figures.
satela [25.4K]

Answer:

The partial pressure of argon in the jar is 0.944 kilopascal.

Explanation:

Step 1: Data given

Volume of the jar of air = 25.0 L

Number of moles argon = 0.0104 moles

Temperature = 273 K

Step 2: Calculate the pressure of argon with the ideal gas law

p*V = nRT

p = (nRT)/V

⇒ with n = the number of moles of argon = 0.0104 moles

⇒ with R = the gas constant = 0.0821 L*atm/mol*K

⇒ with T = the temperature = 273 K

⇒ with V = the volume of the jar = 25.0 L

p = (0.0104 * 0.0821 * 273)/25.0

p = 0.00932 atm

1 atm =101.3 kPa

0.00932 atm = 101.3 * 0.00932 = 0.944 kPa

The partial pressure of argon in the jar is 0.944 kilopascal.

5 0
3 years ago
Question 4 A mixture of xenon and oxygen gas is compressed from a volume of to a volume of , while the pressure is held constant
Misha Larkins [42]

Answer:

W = - 1218 atm L

Explanation:

Complete question

A mixture of krypton and oxygen gas is expanded from a volume of 23.0L to a volume of 81.0L, while the pressure is held constant at 21.0atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

Solution

As we know that -

Work done is equal to the product of pressure applied and change in the difference of volume of two liquids.

This can be represented mathematically as follows -

W = -P*(V_2-V_1)\\

Where W represents the work done

P represents the change in pressure

V_2 is the final volume  and

V_1 is the initial volume

Substituting the given values in above equation, we get -

W = - 21 * (81 -23)\\

W = - 1218 atm L

8 0
3 years ago
Chemical reaction is at equilibrium when ________________.A, chemical reaction is at equilibrium when there is no reverse reacti
77julia77 [94]

Answer:

B. the rate of the forward reaction equals the rate of the reverse reaction.

Explanation:

Equilibrium -

In a chemical reaction , a point or stage is reached , where the rate of forward reaction , becomes equal to the rate of reverse reaction , is referred to as the stage of equilibrium .

In this very stage the concentration on the reactant as well as product side remains constant .

Hence , from the given information of the question ,

The correct option is b.

7 0
3 years ago
What do oxidation reactions produce during the electrolysis of water?
jok3333 [9.3K]
Hydrogen gas, oxygen gas and water

4H2O (l) ---> 2H2O (l) + O2 (g) + 2H2 (g)
8 0
3 years ago
Read 2 more answers
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