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Over [174]
3 years ago
14

How many copies of each chromosome are found in most animal cells?

Biology
1 answer:
lys-0071 [83]3 years ago
8 0
Normally two copies of each chromosome (diploid) are found in most animal cells. The only animal cells that do not contain pairs of chromosomes are reproductive cells, or gametes, which carry just one copy of each chromosome (haploid). When two reproductive cells unite, they become a single cell that contain two copies of each chromosome. 
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Gravity has a higher effect on what kind of vehicles?
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4 years ago
Why does a virus lethal to us not infect animals? I know that RNA viruses mutate at 10,000 to a million times faster than DNA vi
Setler [38]

The virus needs to speak the molecular language of cells. This is how he manages to dominate and enslave them so that they become factories for new viruses, producing the proteins that the infectious agent requires to assemble its descendants. If this conversation is not fine-tuned, even if the virus has the key and enters, it is doomed to failure.

<h3>Why does a virus lethal to us not infect animals?</h3>

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8 0
2 years ago
Watery clay soil slides down a mountain. This is an example of...
zheka24 [161]

Answer:

Mudslide

Explanation:

This is an example of a mudslide. Because it is on a mountain and it is sliding down hill that is why it is called a slide and because it is picking up eroded rocks, mud and grass it is called a mudslide.

7 0
3 years ago
small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi
irina [24]

Answer:

Frequency of p = 0.684

Frequency of p = 0.316

Number of individuals with homozygous dominant (AA) = 47

Number of individuals with heterozygous (Aa)= 43

Number of individuals with homozygous recessive (aa) = 10

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals (q^{2}) is \frac{10}{100} = 0.1

Now, q will be

= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316

As per Hardy Weinberg's equation -

p + q = 1

Substituting the value of q in above equation, we get -

p + 0.316 = 1p = 1 -0.316\\p = 0.684

Now the frequency of homozygous dominant (AA) will be

p^{2} = 0.684^{2} \\= 0.467

Hence, out of 100 people 0.467 * 100 = 46.7 or 47 people are homozygous dominant (AA)

Like wise out of 100 people 0.1 * 100 = 10 people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

p^{2} + q^{2} + 2pq = 1\\

Substituting the values in above equation, we get -

0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433

So, out of 100 people 0.433 * 100 = 43.3 or 43 people are heterozygous (Aa)

7 0
3 years ago
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