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Nikolay [14]
3 years ago
15

The width of a rectangle is 8 inches longer than its length. The perimeter is 104 inches.

Mathematics
2 answers:
Kisachek [45]3 years ago
7 0

Answer:

Width of one side is 30 inches, Length of one side is 22 Inches and Areas is 660 Inches Squared

Step-by-step explanation:

W= 8 + L

P = ( W x 2 ) + ( L x 2 )

104 = 2( 8 + L )  + ( L x 2 )

104 = 16 + 2L + ( L x 2 )

104 = 16 + 2L + 2L

104 = 16 + 4L

-16     -16  

88 = 4L

88 / 4 = 4L / 4

22 = L

W  = 8 + 22

W = 30

Area = L x W

A = 22 * 30

A = 660

Vesna [10]3 years ago
6 0

Answer:

The width of the rectangle is 56 and the length is 48

Step-by-step explanation:

divide the perimeter in half (52 + 52)

then subtract 4 from one of the 52's

you get the answer of 56 and 48

Your answer can be checked by conferming that 56 - 48 = 8 so the width of a rectangle is 8 inches longer than its length.

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Alejandra plans to sew fringe on a scarf. The scarf is shaped rectangle. The length of the scarf is 48 inches. The width is one
aleksandr82 [10.1K]
Ok so you will be finding the perimeter of this rectangle. The formula is P(perimeter)=2L(length) + 2W(width)

so the length is 48 and the width is 1/2 of 48, and we all know that 1/2 of 48 = 24 right? so in the formula is says 2L so we will take 48 and multiply it by 2 and get 96. The same way with the width. 24 times 2 = 48 so then we add them together and get 144. Therefore the perimeter and the length of fringe that she will use (or how ever you say it) will be 144 inches.

Hope this helps!;)
5 0
3 years ago
Point P was rotated by 135 ° (the center of rotation is indicated).
Anika [276]

Answer:

looking at it I think B is P from another angle

8 0
2 years ago
To play basketball with her friends, Evangeline needs to pump air in her ball, which is completely deflated. Before inflating it
Nadya [2.5K]

Answer:

ρ_air = 0.15544 kg/m^3

Step-by-step explanation:

Solution:-

- The deflated ball ( no air ) initially weighs:

                             m1 = 0.615 kg

- The air is pumped into the ball and weight again. The new reading of the ball's weight is:

                            m2 = 0.624 kg

- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.

                           m_air = Δm = m2 - m1

                           m_air = 0.624 - 0.615

                           m_air = 0.009 kg

- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:

                         V_air = 4*π*r^3 / 3

                         V_air = 4*π*0.24^3 / 3

                         V_air = 0.05790 m^3  

 

- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:

                         ρ_air = m_air / V_air

                         ρ_air = 0.009 / 0.05790

Answer:            ρ_air = 0.15544 kg/m^3                      

4 0
3 years ago
Read 2 more answers
Plz help fast will mark brainliest!!!
quester [9]

Answer:

well the answer is 0.185

Step-by-step explanation:

5 0
2 years ago
Find the values of b <br>b²= 256<br>b=?​
ehidna [41]

Answer:

if b²=256

then b=16

....................

5 0
2 years ago
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