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tester [92]
3 years ago
15

-2(4-x)=12x-3 need help please

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
3 0
-8+2x=12x-3
Subtract 2x from both sides

-8=10x-3
Add 3 to both sides
-5=10x
Divide both sides by 10
-5/10 = x

-1/2= x
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write the equaion of a line in slope-intercept form if the slope is 1/5 and the y-intercept is -9 explain please
faust18 [17]

Answer:

y = \frac{1}{5} x - 9

Step-by-step explanation:

The slope-intercept form is y = mx + b, where:

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b = y-intercept.

The slope (m) tells you the steepness of the line. It is the average rate of change which measures how the y-value changes for each one-unit change in the x-value. Hence, slope = \frac{rise}{run}.  So the given slope of 1/5 means that for every 1 unit change in the y-value, the x-value changes by 5 units (you go up 1 unit, and "run" 5 units to the right).

Next, the y-intercept is the point on the graph where it crosses the y-axis, and has the coordinates, (0, b). It is also the value of y when x = 0. Since you're given the y-intercept of -9, then that means that it is the y-coordinate of (0, <em>b</em>). So, it becomes (0, -9).

Now that we have our slope (<em>m </em>) = 1/5, and the y-intercept (<em>b </em>) = -9, we can write the equation of the line as:

y = \frac{1}{5} x - 9

(I'm also including a screenshot of the line where it shows the y-intercept of (0, -9) on the graph).  

Please mark my answers as the Brainliest if you find my explanations helpful :)

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