122.1 or 122
becuase the original answer is 122.13 and the 3 gets out becuase it rounds down and so does the 1
Try multiplying the original price by the decimal so for example 22.50x0.18

Now, If the exponent was negative like you asked....
The answer to your question is the inequality sign.
Answer:
Step-by-step explanation:
Verifying pairs:
(1,0)
- 0 = 6*1 - 2
- 0 = 4 - incorrect
(5, 28)
- 28 = 6*5 - 2
- 28 = 30 -2
- 28 = 28 - correct
(6, 20)
- 20 = 6*6 - 2
- 20 = 36 - 2
- 20 = 34 - incorrect
(3, 19)
- 19 = 6*3 - 2
- 19 = 18 - 2
- 19 = 16 - incorrect