Answer:
Option d. the initial amount of money placed in the savings account
Step-by-step explanation:
we have
This is a exponential function of the form
where
a is the initial value
r is the growth rate
(1+r) is the base
x is the number of years
f(x) is the amount of money in a savings account
In this problem we have
a=$3,005
r=0.03=3%
(1+r)=1.03
therefore
3,005 represent the initial value ( the amount of money for the value of x equal to zero)
The given distance of 5.20 would be A.
Replace A with 5.20 to solve for T.
T = 5.20^3/2
T = 11.9 years.
Answer:
(
−
2
)
=
−
1
4
(
−
8
)
(x-2)=\frac{-1}{4}(x-8)
(x−2)=4−1(x−8)
Solve
1
Eliminate redundant parentheses
(
−
2
)
=
−
1
4
(
−
8
)
−
2
=
−
1
4
(
−
8
)
2
Combine multiplied terms into a single fraction
−
2
=
−
1
4
(
−
8
)
−
2
=
−
1
(
−
8
)
4
3
Distribute
−
2
=
−
1
(
−
8
)
4
−
2
=
−
+
8
4
4
Add
2
2
2
to both sides of the equation
−
2
=
−
+
8
4
−
2
+
2
=
−
+
8
4
+
2
5
Simplify
Add the numbers
=
−
+
8
4
+
2
Solution
=
1
6
5
Step-by-step explanation:
(-1.2,-2.0) and (1.9,2.2) are the best approximations of the solutions to this system.
Option B
<u>Step-by-step explanation:</u>
Here, we have a graph of two functions from which we need to find the approximate value of common solutions. Let's find this:
First look at where we have intersection points, In first quadrant & in third quadrant.
<u>At first quadrant:</u>
Draw perpendicular lines from x-axis & y-axis from this point . After doing this we can clearly see that the perpendicular lines cut x-axis at x=1.9 and y-axis at y=2.2. So, one point is (1.9,2.2)
<u>At Third quadrant:</u>
Draw perpendicular lines from x-axis & y-axis from this point. After doing this we can clearly see that the perpendicular lines cut x-axis at x=-1.2 and y-axis at y= -2.0. So, other point is (-1.2,-2.0).
