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3 years ago

Robert is writing a paper for language arts class. He can write 2/3 of a page in 1/4 of an hour. At what rate is Robert writing?

Mathematics

1 answer:

Irina-Kira [14]3 years ago

6 0

Answer:

A) 2 2/3 pages per hour

Step-by-step explanation:

You would multiply 1/4 times 4 to get 1 hour

then you would multiply 2/3 times 4 which is 2 2/3

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Compare the two ratios by entering >, < , or = in the box.<br> 1/8 3/20

Elanso [62]

In order to compare the fractions, we need to convert them into decimal form,
1/8 = 0.125
3/20 = 0.15
As 0.15 > 0.125

In short, Your Answer would be 3/20 > 1/8

Hope this helps!

5 0

3 years ago

Read 2 more answers

576 = 96 × 6

aliya0001 [1]

Answer:

Step-by-step explanation

A.96=6+576

B.576=96+6

C. 96=6×576

D. 576=96×6

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3 years ago

A. What is the volume, in cubic feet, of the box in the diagram?

Allisa [31]

Volume is a three-dimensional scalar quantity. The number of boxes that can fit in the cargo hold of the truck is 54.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

The volume of the box = Volume of the cube = a³ = (2.50)³ = 15.625 ft³

The volume of cargo hold = 7.50 × 7.50 × 15 = 843.75 ft³

Now, the number of boxes that can fit in the cargo hold of the truck will be,

Number of boxes = (Volume of truck container)/(Volume of box)

= 843.75/15.625

= 54

Hence, the number of boxes that can fit in the cargo hold of the truck is 54.

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2 years ago

What is the sum of the sequence 152,138,124, ... if there are 24 terms?

N76 [4]

Answer: -216

Step-by-step explanation:

To solve the exercise you must use the formula shown below:

$Sn=\frac{(a_1+a_n)n}{2}$

Where:

$a_1=152\\a_n=a_{24}$

You should find $a_{24}$

The formula to find it is:

$a_n=a_1+(n-1)d$

Where d is the difference between two consecutive terms.

$d=138-152=-14$

Then:

$a_{24}=152+(24-1)(14)=-170$

Substitute it into the first formula. Therefore, you obtain:

$S_{24}=\frac{(152-170)(24)}{2}=-216$

3 0

3 years ago

Read 2 more answers

I answered it but I just need someone to answer just to make sure mine are right

Artemon [7]

<h2>The missing measures of the angles are:</h2>

$m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

<u>Given</u>:

$m\angle Z = 138^{\circ}$

<em><u>Note the following:</u></em>

An equilateral triangle has all its three angles equal to each other. Each angle = $60^{\circ}$ .

This implies that, since $\triangle WXY$ is equilateral, therefore, $m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}$

Base angles of an isosceles triangle are congruent to each other.

This implies that, since $\triangle WZY$ is isosceles, therefore, $m\angle 3 = \angle 5$

Applying the above stated, let's find the measure of each angle:

Find $m\angle 1$

$m\angle 1 = 60^{\circ}$ (an angle in an equilateral triangle equals 60 degrees)

Find $m\angle 2$

$m\angle 2 = 60 - m \angle 3$

$m\angle 2 = 60 -\frac{1}{2}(180 - 138)$ $(Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}$

Find $m\angle 3$ and $m\angle 5$ (base angles of isosceles triangle WZY)

$m\angle 3 = \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 3 = \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}$

$m\angle3 = m\angle 5$ (base angles of isosceles triangle are congruent)

Therefore,

$m\angle5 = 21^{\circ}$

Find $m\angle 4$

$m\angle 4 = 60 - m\angle 5$

Substitute

$m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}$

The missing measures of the angles are:

$m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

Learn more here:

brainly.com/question/2944195

5 0

3 years ago