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Rainbow [258]
2 years ago
5

The product of a constant factor 15 and a 2-term factor x+4

Mathematics
1 answer:
dezoksy [38]2 years ago
6 0
The product of 15 and x+4 is 15(x+4) = 15x+60. This is a linear binomial.

4x^3-2x-9-(2x^3) is a cubic trinomial. In your original question, I'm not sure what the 5x+3 means.
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What is the ratio of 14 by 8 1/2 when the answer says _ to 1?
bearhunter [10]
Zdnxfjncgfgnxfgnxfgnbfxgfnxdfngnxf
5 0
2 years ago
Ecuaciones con resultado 17
babymother [125]

Answer:

x-1= -18

x = -18 +1

x = -17

2x - 4 = - 38

2x = -38 + 4

2x = -34

x = -34/2

x = -17

Step-by-step explanation:

6 0
2 years ago
Suppose that the probability that a child living in an urban area in the United States is obese is 20%. If a social worker sees
Levart [38]

Answer:

The probability the event that none of them are obese is 0.0352.

Step-by-step explanation:

<h3>Binomial distribution:</h3>

A discrete random variable X having to the set {0,1,2,3....,n} as the spectrum, is said to have binomial distribution with parameters n= the number of trial, and p= probability of successes on an individual trial , if the p.m.f of X is given by,

P(X=x)=\left(\begin{array}{c}n\\x\end{array}\right) p^x(1-p)^{n-x} for x=0,1,2,...,n

                =0                               elsewhere.

where 0<p<1 and  n an positive integer,

Given that,

The probability of the event that a child living in an urban area in the united state is obese is 20%.

n=Number of children = 15, p= 20%= 0.20.

The probability the event that none of them are obese is

=P(X=0)

=\left(\begin{array}{c}15\\0\end{array}\right) (0.20)^0(1-0.20)^{15-0}

=0.0352

7 0
3 years ago
1. (5pt) In a recent New York City marathon, 25,221 men finished and 253 dropped out. Also,
gladu [14]

Answer:

(a) Explained below.

(b) The 99% confidence interval for the difference between proportions is (-0.00094, 0.00494).

Step-by-step explanation:

The information provided is:

n (Men who finished the marathon) = 25,221

n (Women who finished the marathon) = 12,883

Compute the proportion of men and women who finished the marathon as follows:

\hat p_{1}=\frac{25221}{25221 +253}=0.99\\\\\hat p_{2}=\frac{12883 }{12883+163}=0.988

The combined proportion is:

\hat P=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}\\\\=\frac{25221+12883}{38520}\\\\=0.989

(a)

The hypothesis is:

<em>H</em>₀: The rate of those who finish the marathon is the same for men and women, i.e. <em>p</em>₁ - <em>p</em>₂ = 0.

<em>Hₐ</em>: The rate of those who finish the marathon is not same for men and women, i.e. <em>p</em>₁ - <em>p</em>₂ ≠ 0.

Compute the test statistic as follows:

Z=\frac{\hat p_{1}-\hat p_{2}}{\sqrt{\hat P(1-\hat P)\cdot [\frac{1}{n_{1}}+\frac{1}{n_{2}}]}}

   =\frac{0.99-0.988}{\sqrt{0.989(1-0.989)\times[\frac{1}{25474}+\frac{1}{13046}]}}\\\\=1.78

Compute the <em>p</em>-value as follows:

p-value=2\times P(Z>1.78)\\\\=2\times 0.03754\\\\=0.07508\\\\\approx 0.075

The <em>p</em>-value of the test is more than the significance level. The null hypothesis was failed to be rejected.

Thus, concluding that the rate of those who finish is the same for men and women.

(b)

Compute the 99% confidence interval for the difference between proportions as follows:

The critical value of <em>z</em> for 99% confidence level is 2.58.

CI=(\hat p_{1}-\hat p_{2})\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p_{1}(1-\hat p_{1})}{n_{1}}+\frac{\hat p_{2}(1-\hat p_{2})}{n_{2}}}

     =(0.99-0.988)\pm 2.58\times\sqrt{\frac{0.99(1-0.99)}{25474}+\frac{0.988(1-0.988)}{13046}}\\\\=0.002\pm 0.00294\\\\=(-0.00094, 0.00494)\\\\

Thu, the 99% confidence interval for the difference between proportions is (-0.00094, 0.00494).

6 0
3 years ago
4.13 rounded to one decimal point
arlik [135]
The answer is 4.1
If the number is below 5, you round down, if it's 5 or above, you round up.
8 0
3 years ago
Read 2 more answers
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