Answer:
The constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
Consider the provided information.
It is given that the mass of the ball is m = 2.2 kg
The initial velocity of the ball towards left is 7.4 m/s
So the momentum of the ball when it strikes is = 
The final velocity of the ball is -6.2 m/s
So the momentum of the ball when it strikes back is = 
Thus change in moment is: 
The duration of force exerted on the ball t = 0.25 s
Therefore, the constant force exerted on the ball by the wall is:

Hence, the constant force exerted on the ball by the wall is 119.68 N.
21.50 x 25 = 537.50
10.75 x 5 = 53.75
537.50 + 53.75 = 591.25
1. Julia's ≤ Rachel's hair
2. 40 < 74
the net is pretty much the net of a long box, kinda like the one in the example in the picture below. Due to that, we can pretty much assume the two sides sticking up and down, are just two small 6x3 rectangles, namely, they have a height of 3, reason why we assume that, if that if we fold the other sides to make out the box, those two sides sticking out, must be 3m to neatly snugfit.
now, if we close the box as it stands, the sides(laterals) will be on the left-right sides two 3x15 rectangles, and on the front-back sides, two 6x15 rectangles.
we're excluding the top and bottom sides, because those are not "laterals", or sides of the box.
