All categories

3 years ago

Find the exact value of sec(-4π/3

1 answer:

3 0

<span>Find the exact value of sec(-4π/3). Note that one full rotation, clockwise, would be -2pi. We have to determine the Quadrant in which this angle -4pi/3 lies. Think of this as 4(-pi/3), or 4(-60 degrees). Starting at the positive x-axis and rotating clockwise, we reach -60, -120, -180 and -240 degrees. This is in Q III. The ray representing -240 has adj side = -1 and opp side = to sqrt(3).

Using the Pyth. Theorem to find the length of the hypo, we get hyp = 2.

Thus, the secant of this angle in QIII is hyp / adj, or 2 / sqrt(3) (answer). This could also be written as (2/3)sqrt(3).

</span>

You might be interested in

When determining the volume of a shape, you should use cubic units in your final answer. true or false.

Phoenix [80]

Answer:

true

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A 2.2 kg ball strikes a wall with a velocity of 7.4 m/s to the left. The ball bounces off with a velocity of 6.2 m/s to the righ

Naya [18.7K]

Answer:

The constant force exerted on the ball by the wall is 119.68 N.

Step-by-step explanation:

Consider the provided information.

It is given that the mass of the ball is m = 2.2 kg

The initial velocity of the ball towards left is 7.4 m/s

So the momentum of the ball when it strikes is = $2.2\times 7.4=16.28$

The final velocity of the ball is -6.2 m/s

So the momentum of the ball when it strikes back is = $2.2\times -6.2=-13.64$

Thus change in moment is: $16.28-(-13.64)=29.92$

The duration of force exerted on the ball t = 0.25 s

Therefore, the constant force exerted on the ball by the wall is:

$\frac{29.92}{0.25}=119.68$

Hence, the constant force exerted on the ball by the wall is 119.68 N.

6 0

3 years ago

Evan earns $21.50 per hour for 25 hours and time and a half for overtime. If he worked 5 hours

Andrei [34K]

21.50 x 25 = 537.50
10.75 x 5 = 53.75

537.50 + 53.75 = 591.25

4 0

3 years ago

Write an inequality that represents each sentence.

ivann1987 [24]

1. Julia's ≤ Rachel's hair

2. 40 < 74

7 0

3 years ago

I don’t get it. <br> Use the net to find the lateral area of the prism.

sesenic [268]

the net is pretty much the net of a long box, kinda like the one in the example in the picture below. Due to that, we can pretty much assume the two sides sticking up and down, are just two small 6x3 rectangles, namely, they have a height of 3, reason why we assume that, if that if we fold the other sides to make out the box, those two sides sticking out, must be 3m to neatly snugfit.

now, if we close the box as it stands, the sides(laterals) will be on the left-right sides two 3x15 rectangles, and on the front-back sides, two 6x15 rectangles.

we're excluding the top and bottom sides, because those are not "laterals", or sides of the box.

$\bf \stackrel{\textit{two rectangles, left and right}}{2(3\cdot 15)}+\stackrel{\textit{two rectangles, front and back}}{2(6\cdot 15)}
\\\\\\
90+180\implies 270$

6 0

3 years ago