Newton's Law of Cooling
Tf=Ts+(Ti-Ts)e^(-kt) where Tf is temp at time t, Ts is temp of surroundings, Ti is temp of object/fluid. So we need to find k first.
200=68+(210-68)e^(-10k)
132=142e^(-10k)
132/142=e^(-10k)
ln(132/142)=-10k
k=-ln(132/142)/10
k≈0.0073 so
T(t)=68+142e^(-0.0073t) so how long until it reaches 180°?
180=68+142e^(-0.0073t)
112=142e^(-0.0073t)
112/142=e^(-0.0073t)
ln(112/142)=-0.0073t
t= -ln(112/142)/(0.0073)
t≈32.51 minutes
Answer: 4.3478 or 100/23
Step-by-step explanation:
Set the y values equal to each other since they are the same unknown (x). You end up with 100=23x, solve for x. Move the 23 over to the other side by using division. x=100/23. If you need it in decimal form, 100÷23=4.347826087
Answer:
because when the value of x is replaced in the factorisation it Will be equivalent to 100
