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3 years ago

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the speed of sound is deterimened by the temperature of the air. The speed, c, in meters per second is given by c=331.5sqrt(1+t/

273.15) where t is the temperature of air in degrees Celsius. How fast will sound travel when the temperature is 55 degrees Celsius?

1 answer:

rodikova [14]3 years ago

4 0

Speed = 331.5*sqrt(1+55/273.15)=365.15

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explanation:
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2 years ago

If the coordinates of point P are (0,8) and the coordinates of point Q are ( 4,2), Which of the following points represents the

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The coordinates of the midpoint are just the average of the endpoint coordinates ...
x-mid is the average of the end-x's, and y-mid is the average of the end-y's.

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3 years ago

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Sliva [168]

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<u>Solution:</u>

Given, two points are (2, -1) and (4, 5)

We have to find that a line that passes through the given two points.

First let us find the slope of the line that passes through given two points.

So, slope of line "m" is given as:

$\mathrm{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text { where, }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are two points on line. }$

So slope of our line = $\frac{5-(-1)}{4-2}=\frac{5+1}{2}=3$

Now, let us find the line equation using point slope form:

$y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }$

Then equation of line is,

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y – 5 = 3x – 12

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3 years ago

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ElenaW [278]

Check the picture below.

$\bf \qquad \textit{initial velocity}\\\\
\begin{array}{llll}
\qquad \textit{in meters}\\\\
h(t) = -4.9t^2+v_ot+h_o
\end{array} 
\quad 
\begin{cases}
v_o=\textit{initial velocity of the object}\\
\qquad \qquad 25\\
h_o=\textit{initial height of the object}\\
\qquad \qquad 11\\
h=\textit{height of the object at "t" seconds}
\end{cases}
\\\\\\
h(t)=-4.9t^2+25t+11\\\\
-------------------------------\\\\$

$\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lccclll}
h(t) = &{{ -4.9}}x^2&{{ +25}}x&{{ +11}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
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3 years ago

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