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3 years ago

What additional information would you need to prove that ΔABC ≅ ΔDEF by ASA

1 answer:

3 0

What do you mean? You just need to prove there are two angles and the side between these two angles are the same in each triangle. One of the possible <span>combinations could be </span>∠BAC=∠FDE, ∠ABC= ∠DEF, and AB=DE.

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Rujuan

Leona [35]

Answer:

Sin X=Cos Y

Step-by-step explanation:

Objective: Understand trigonometric relations such that

Cosine and Sine are similar to complementary angles that if X+Y are complementary angles,

Cos X= Sin Y and Cos Y= Sin X

7 0

3 years ago

The sum of the angles of a triangle is 180°. If one angle of a triangle measures x and the second angle measures (5x +19)º

lapo4ka [179]

Answer:

third angle = (-6x + 161)°

Step-by-step explanation:

180° = (x)° + (5x + 19)° + third angle →

180° = (6x + 19)° + third angle →

180° – (6x + 19)° = (6x + 19)° + third angle – (6x + 19)° →

180° – (6x + 19)° = third angle →

180° + -(6x + 19)° = third angle →

180° + (-6x)° + (-19)° = third angle

180° – 6x° – 19° = third angle

(180° – 19°) – 6x° = third angle

161° – 6x° = third angle

third angle = 161 – 6x°

third angle = -6x° + 161°

third angle = (-6x + 161)°

8 0

2 years ago

Help me simplify this, please!!

OlgaM077 [116]

$- \sqrt[3]{2 x^{4} y^{2} } *3 \sqrt[3]{20 x^{5}y } =-3 \sqrt[3]{2 x^{4} y^{2}20 x^{5}y} = \\ \\ =-3 \sqrt[3]{40 x^{9} y^{3} } =-3 \sqrt[3]{2 ^{3}*5* x^{9} y^{3} } = \\ \\ =-3*2 ^{ \frac{3}{3} } * x^{ \frac{9}{3} } * y^{ \frac{3}{3} } \sqrt[3]{5} =-6 x^{3} y \sqrt[3]{5}$
Answer: B.

6 0

3 years ago

3xy - ² + 4x for x = -2, y = - and = 6?

Kitty [74]

Answer:

See below

Step-by-step explanation:

Not sure what you are asking....do you want to know what y is when x = -2 and the equation = 6 ?

3 xy^2 + 4x = 6 or is that 3 xy^(-2) + 4x = 6

Could use some serious editing of your question if you are able ....

7 0

1 year ago

a cargo ship arrived at Kingston Harbour carrying 403,172 kilograms of flour. All the flour was tranfered to 5 trains and 9 truc

IrinaVladis [17]

Each train carried 64141 kg of flour and each truck carried 9163 kg of flour.

Step-by-step explanation:

Let the no. of kg of flour carried by each train be 'a'

Let the no. of kg of flour carried by each truck be 'b'

Total flour = 403172 kg

No. Of trains = 5

No. of trucks = 9

a = 7(b)

5a + 9b = 403172

5(7b) + 9b = 403172

35b + 9b = 403172

44b = 403172

b = 403172/44

b = 9163

Each truck carried 9163 kg of flour.

a = 7b

a = 7(9163)

a = 64141

Each train carried 64141 kg of flour.

4 0

3 years ago