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german
3 years ago
9

A tire dealer sells Supreme tires for $48 each and Prestige tires for $56 each. During one week, thhe sales of both tires total

is $2008. If 11 prestige tires were sold, write and solve a linear equation to find the number of Supreme tires sold.
Mathematics
1 answer:
Anna71 [15]3 years ago
5 0
<span>48s + 56p = 2008 Let P=Prestige tires and S=Supreme</span>
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Please help this is due tomorrow
Lostsunrise [7]

\sf \left(\dfrac{1}{7}\right)^3\ is\ basically\ like\ saying\ you're\ multiplying\ \dfrac{1}{7}\ by\ \dfrac{1}{7},\ three\ times.

\implies\ \sf \dfrac{1}{7}\ \times\ \dfrac{1}{7}\ \times\ \dfrac{1}{7}\\\\\\\implies\ \dfrac{1}{343}

Therefore, (1/7)³ = 1/343, implying that the answer is option (D).

Hope it helps. :)

7 0
3 years ago
Read 2 more answers
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Gelneren [198K]

Answer:

4

Step-by-step explanation:

Hurley drank between 4 and 5 liters of water for 8 different days and drank between 1 or 2 liters of water on 4 different days. To find the answer we have to use the following equation.

# of days Hurley drank (4-5 L) - # of days Hurley drank (1-2 L) = # of more days

8 - 4 = 4

4 0
3 years ago
Let set C = {1, 2, 3, 4, 5, 6, 7, 8} and set D = {2, 4, 6, 8}.
g100num [7]
<span>1. If it is intersection then it SHOULD be included in both the sets right? Now we know that odd numbers from 1-100 but the second set are multiples of 5 from 50-150! So we mainly need to look for common numbers which are ODD and are a MULTIPLE OF 5 BETWEEN 50 - 100!! So A={51,53,57,59,61......99} B={55,60,65,70.......95} [We stop till 100 because set A has no such element] So what is A ∩ B here? A ∩ B = {All odd numbers and multiples of 5 between 50 - 100}

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6 0
3 years ago
Rosa’s employer pays 80% of her health insurance premium and deducts the remainder from her paycheck. Rosa is paid weekly, and t
Lana71 [14]
The answer to your question is b. Hope i helped :)

3 0
3 years ago
Read 2 more answers
Pre Algebra
Maslowich

Answer:

A. 36

B. 3.5

Step-by-step explanation:

To solve for the first equation, we could represent the hot dogs as h(1.75-.50), since they are losing .50 cents for each hot dog, <em>h,</em> they make.

Since they want to know how many hot dogs they have to sell to equal the amount of money they spent, we can represent it as an equal sign.

Now all we have to do is add the constants. Add 12 to our overall equation and subtract 57, since the <u>received</u> $12 in donations and <u>lost</u> $57.

Our equation is 12+h1.75=57+.5h We can just put all of the negative numbers on one side and the positive numbers on the other to find out when they will be equal.

First, subtract 12 from 57.

h1.75=45+.5h

Now subtract .5h from both sides.

h1.25=45

Finally, divide both sides by 1.25.

h=36.

They will have to sell 36 hot dogs.

If they want to sell halve the hotdogs for the same price, simply multiply the current price by 2.

The hotdogs will have to cost $3.5.

Hope this helps!

4 0
3 years ago
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