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Answer:
a) 0.69
The probability that a randomly selected 10-year old child will be more than 51.75 inches tall
P(X>51.75 ) = 0.6915
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
<em>Given mean of the Population = 54.6 inches</em>
<em>Given standard deviation of the Population = 5.7 inches</em>
<em>Let 'X' be the random variable of normal distribution</em>
Let 'X' = 51.75 inches
<u><em>Step(ii):</em></u>-
<em>The probability that a randomly selected 10-year old child will be more than 51.75 inches tall</em>
<em>P(X>51.75 ) = P(Z>-0.5)</em>
= 1 - P( Z < -0.5)
= 1 - (0.5 - A(-0.5))
= 1 -0.5 + A(-0.5)
= 0.5 + A(0.5) (∵A(-0.5)= A(0.5)
= 0.5 +0.1915
= 0.6915
<u><em>Conclusion</em></u>:-
<em>The probability that a randomly selected 10-year old child will be more than 51.75 inches tall</em>
<em>P(X>51.75 ) = 0.6915</em>
Answer
Find out the how much money was in the account after years.
To prove
Formula
As given
Tracy deposited $59 into a bank account that earned 3.5% simple interest each year.
Principle = $59
Rate = 3.5 %
i.e
Time = 1.5 years
Put all the values in the equation
= \frac{309.75}{100}[/tex]
= $3.1(approx)
Amount in the account = Principle + Simple interest
= $59 + $ 3.1
= $ 62.1
1 Dollar = 100 cent
Now convert $62.1 into cent.
= 62.1 × 100
= 6210 cent
Therefore the money in the account is 6210 cent .