1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
love history [14]
3 years ago
8

Solve for X: Show me the steps: -3x = 2x + 19

Mathematics
1 answer:
jenyasd209 [6]3 years ago
3 0

\text{Hello there!}\\\\\text{Solve for x:}\\\\-3x = 2x + 19\\\\\text{Subtract 2x from both sides}\\\\-5x=19\\\\\text{Divide both sides by -5}\\\\x= -19/5\,\,\text{or}\,\,x= -3.8

You might be interested in
Who can friend me first<br> also view my profile
gavmur [86]

Answer:

LOL OK

Step-by-step explanation:

HAHAHAHAHAHAHAHAHAHAHAHA

6 0
2 years ago
A 150 no container can hold 23.6 g of aluminum what is the density of the aluminum?
Drupady [299]

Answer:

# The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The volume of the container is 4/17 ≅ 0.235 cm³

# The mass of iron is 1225 g

Step-by-step explanation:

* Lets explain how to solve the problem

- Density is a measurement that compares the amount of matter

 of an object to its volume [ Density = mass/volume]

- Density is found by dividing the mass of an object by its volume

- The unit of measuring density is gram per centimeter³ (milliliter)

* Lets solve the problems

# A container of volume 150 cm³ can hold 23.6 g of aluminum

∵ Density = mass/volume

∵ The mass = 23.6 g

∵ The volume = 150 cm³

∴ The density = 23.6/150 = 59/375 ≅ 0.157 g/cm³

* The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The density of mercury is 13.6 g/cm³ at 23 C°

- A container can hold 3.2 g of mercury at this temperature

∵ Density = mass/volume

∵ The mass = 3.2 g

∵ The density = 13.6 g/cm³

∴ 13.6 = 3.2/volume

- By using cross multiplication

∴ The volume = 3.2/13.6 = 4/17 cm³

* The volume of the container is 4/17 ≅ 0.235 cm³

# The density of the iron is 4.9 g/cm³

- The beaker has a volume 250 ml

∵ Density = mass/volume

∵ The ml = cm³

∴ The volume of the beaker is 250 cm³

∵ The density = 4.9 g/cm³

∴ 4.9 = mass/250

- Multiply both sides by 250

∴ mass = 1225 g

* The mass of iron is 1225 g

7 0
3 years ago
Need help with this question
Veronika [31]
2 is the answer you need
8 0
3 years ago
What is rhe lateral edge on a rectangular prizm
Jlenok [28]
The surface area<span> of a right </span>prism<span> can be calculated using the following formula: SA 5 2B 1 hP, where B is the </span>area<span> of the base, h is the height of the </span>prism<span>, and P is the perimeter of the base. The </span>lateral area<span> of a figure is the </span>area<span> of the non-base faces only.</span>
8 0
2 years ago
Steps for solving rational equations
Murrr4er [49]

Answer:

1. Find the common denominator.

2. Multiply everything by the common denominator.

3. Simplify.

4. Check the answer(s) to make sure there isn't an extraneous solution.

Step-by-step explanation:

Hope this helps!

5 0
2 years ago
Read 2 more answers
Other questions:
  • "Polio has a basic reproduction number (R0) = 5. The vaccine is very good; in fact, polio vaccine is 99% effective when two foll
    8·1 answer
  • Chords AC and BD intersect at the center of circle ABCD. Which is the measure of the minor arc AB?
    7·2 answers
  • Please help me with this question.
    8·2 answers
  • If $516 is invested at an interest rate of 9% per year and is compounded continuously, how much will the investment be worth in
    12·1 answer
  • A piece of chocolate is 4/5 inch long. Meg lays 4 chocolate pieces end to end in a row. How many inches long is the row of choco
    15·1 answer
  • 2369 divided by 6= t
    6·2 answers
  • Evaluate -d - euf-g if d = 5, e = -6, f = 7 and g = -9<br> -27<br> 27<br> - 17<br><br> 17
    6·1 answer
  • Help. pls. i will mark brainliest.
    11·2 answers
  • Part A
    10·1 answer
  • I need so much help please somebody help me
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!