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svlad2 [7]
4 years ago
12

System A

Mathematics
1 answer:
Doss [256]4 years ago
7 0
Both systems will have the same value of x's.
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Find the circumference of the circle and round to the nearest tenth
ikadub [295]

Answer:

circumference of circle = 2×pi×r

circumference of circle = 2×3.14×12.7

circumference of circle = 79.756 in

8 0
3 years ago
Find the volume of a rectangular prism with dimensions 21 in. by 20 in. by 19 in., to the nearest hundredth cubic foot
Maurinko [17]

Answer:

The dimensions of a rectangular prism are 21 in. by 20 in. by 19 in.

To find:

The volume of the rectangular prism.

Solution:

Let the length, breadth and height are 21 in, 20 in and 19 in respectively.

Volume of the rectangular prism is

V=Length\times Breadth\times Height

V=21\times 20\times 19

V=7980

Therefore, the volume of the rectangular prism is 7980 cubic inches.

6 0
3 years ago
A conjecture and the two-column proof used to prove the conjecture are shown.
Ahat [919]

Answer:

Just took the quiz hopefully this helps!

Step-by-step explanation:

4 0
3 years ago
O is the centre of the circle, EF is a tangent, angle BCE=28 degrees, angle ACD=31 degrees.
Yuki888 [10]

Answer:

a. 28˚

b. 76˚

c. 104˚

d. 56˚

Step-by-step explanation

a. because angle between tangent and chord is equal to the angle(s) in alternate segment.

b. because angles in triangles add up to 180˚, 180-28=152 and because isosceles triangle, 152/2=76˚

c. because angles in triangles add up to 180˚ and opposite angles in a cyclic quadrilateral add up to 180˚, 31+76=107, 180-107=73, 73-28=45, angles in triangle so 180-(31+45)=104˚

d. 28*2=56˚ because angles at circumference are half angles at centre

4 0
3 years ago
There are 515 students who attend central middle school. Three out of every 5 students live within 1 mile of the school. How man
AleksandrR [38]

Answer:

103 students live 1 mile away from the school.

Step-by-step explanation:

First dicide what the problem is really asking you then you end up getting divisoin them divide 515/3.

5 0
3 years ago
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