Question

What are the four consecutive numbers whose sum is 50?

Answer 1

X+x+1+x+2+x+3=50
4x+6=50/-6
4x=50-6=44
x=44:4=11
⇒The 1st number is 11, the 2nd is 12, the 3rd is 13 and the 4th is 14.
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11+12+13+14=50

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