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3 years ago

12

Factor x^2 - 8x + 16

1 answer:

zlopas [31]3 years ago

6 0

X^2-8x+16 = x^2-2*x*4+4^x => (x-4)^2 => C

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K-2=4<br> Help me please

mart [117]

Answer:

k = 6

Step-by-step explanation:

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3 years ago

Read 2 more answers

A car manufacturer announced that next year the price of a certain model car would increase by 5.5 %. This year the price is $1

zloy xaker [14]

Answer:

Increase: $969.93 New Price: $18,604

Step-by-step explanation:

I got this answer by finding out how much of the initial price 5.5% was, it ended being 969.925 so I rounded that to 969.23 so that I may found how much the price increased, then I added the increase price to the initial price so that I may find out how much the car would cost next year which is, $18,604.

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3 years ago

Mathematics can uh solve this please

guajiro [1.7K]

Answer:

$a^3 + 1 = 0$

Step-by-step explanation:

We start with the equation:

$a + \frac{1}{a} = 1$

We want to find the value of:

$a^3 + 1 =$

We can start with our previous equation and multiply both sides by a:

$(a + \frac{1}{a})*a = 1*a\\a^2 + 1 = a$

Now we can rewrite our initial expression as:

$a = 1 - \frac{1}{a}$

Replacing that in the right side, we get:

$a^2 + 1 = a = 1 - \frac{1}{a}$

Now again, let's multiply both sides by a

$a*(a^2 + 1) = a*(1 - \frac{1}{a} )\\a^3 + a = a - a/a\\a^3 + a = a - 1\\a^3 = -1\\a^3 + 1 = 0$

So we can conclude that:

$a^3 + 1 = 0$

3 0

3 years ago

An airplane traveled 700 kilometers in two hours during a trip. What was the average speed of the plane during the trip?

Igoryamba

9514 1404 393

Answer:

350 km/h

Step-by-step explanation:

Speed = distance/time

speed = (700 km)/(2 h) = 350 km/h

8 0

3 years ago

An article reports "attendance dropped 7% this year, to 6854." What was the attendance before the drop? (Round your answer to th

Masja [62]

Answer:

7370

Step-by-step explanation:

Let x represent attendance before drop.

We have been given that an article reports attendance dropped 7% this year, to 6854. We are asked to find the attendance before the drop.

Since attendance dropped by 7%, this means that attendance after drop was 93% of x.

We can represent this information in an equation as:

$x-\frac{7}{100}x=6854$

$x-0.07x=6854$

$0.93x=6854$

$\frac{0.93x}{0.93}=\frac{6854}{0.93}$

$x=7369.89247$

$x\approx 7370$

Therefore, the attendance before drop was 7370.

4 0

4 years ago