1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
swat32
1 year ago
9

What would this be???

Mathematics
1 answer:
Ilia_Sergeevich [38]1 year ago
7 0
This is a representation of a dilation, and would therefore mean you multiply the side lengths all by the scale factor (which is 3). I cannot do this for you because I do not have the graph for it. You’ll have to multiply each side length by 3 and plot the points accordingly.
You might be interested in
Solve the equation. n+34=14
wlad13 [49]

Answer:

n = -20

Step-by-step explanation:

Subtract 34 on both sides of the equation:

n = 14 - 34

n = -20

Hope this helps!

4 0
2 years ago
Read 2 more answers
Show YOUR Work What is the circumference, in inches, of a circle with a radius of 8 inches? (C=2Лr)
miskamm [114]

Answer:

The answer is 50.24

Step-by-step explanation:

C=2Лr

C=16Л

C=50.24

4 0
2 years ago
The number of salmon swimming upstream to spawn is approximated by the following function:
umka2103 [35]

Answer:

The water temperature that produces the maximum number of salmon swimming upstream is approximately 12.305 degrees Celsius.

Step-by-step explanation:

Let S(x) = -x^{3}+2\cdot x^{2}+405\cdot x +4965, for 6 \leq x \leq 20. x represents the temperature of the water, measured in degrees Celsius, and S is the number of salmon swimming upstream to spawn, dimensionless.

We compute the first and second derivatives of the function:

S'(x) = -3\cdot x^{2}+4\cdot x +405 (Eq. 1)

S''(x) = -6\cdot x +4 (Eq. 2)

Then we equalize (Eq. 1) to zero and solve for x:

-3\cdot x^{2}+4\cdot x +405 = 0

And all roots are found by Quadratic Formula:

x_{1} \approx 12.305\,^{\circ}C, x_{2}\approx -10.971\,^{\circ}C

Only the first root is inside the given interval of the function. Hence, the correct answer is:

x \approx 12.305\,^{\circ}C

Now we evaluate the second derivative at given result. That is:

S''(12.305) = -6\cdot (12.305)+4

S''(12.305) = -69.83

According to the Second Derivative Test, a negative value means that critical value leads to a maximum. In consequence, the water temperature that produces the maximum number of salmon swimming upstream is approximately 12.305 degrees Celsius.

5 0
3 years ago
Can someone help me out? Pls it’s urgent!!! ASAP! (Geometry)<br> “Complete the proof”
Nikitich [7]

1) \overline{WX} \cong \overline{UY}, \angle YXZ \cong \angle XYZ (given)

2) \overline{XY} \perp \overline{XY} (reflexive property)

3) \triangle WXY \cong \triangle UYX (SAS)

4) \overline{WY} \perp\overline{ UX} (CPCTC)

6 0
2 years ago
Plz help ASAP! 10 points
loris [4]
There’s this app called Socratic that you can use. It’s like this one but it’s a little different
4 0
2 years ago
Other questions:
  • The y-value is two more than three times the x-value
    15·1 answer
  • a culture started with 2000 bacteria.after 8 hours it grew to 2400 predict how many bacteria will be present after 19 hours?
    6·1 answer
  • Which set of numbers is correctly ordered from least to greatest?
    15·2 answers
  • Multiply the following: 2 3/8×3 3/7
    9·2 answers
  • For questions 19-22, write a linear equation with the given informatio
    8·1 answer
  • How many ball bearings, each with a diameter of 1 cm, can be made using 5.24 cm3 of molten steel? A) 4. B) 7. C) 8. D) 10
    10·1 answer
  • 2(3 times 3+4 times 4)
    13·2 answers
  • 1. which two types of clouds indicate fair weather?
    10·2 answers
  • Dan spent half of his allowance going to the movies. He washed his family car and earned $6. What is his weekly allowance if he
    13·1 answer
  • The weight of a boy was 15kg last year. If his weight increases by 3kg this year, find the percentage increase in his weight.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!