Answer:
A. 
Step-by-step explanation:
Hi there!
We are given right triangle PQR, with PR=5, RQ=12, and PQ=13
We want to find the value of sin(Q)
Let's first recall that sine is 
In reference to angle Q, PR is the opposite side, RQ is the adjacent side, and PQ is the hypotenuse
So that means that sin(Q) would be 
Substituting the values of PR and PQ gives sin(Q) as , which is A
Hope this helps!
Answer:B 55
Step-by-step explanation:
Step-by-step explanation:
7x+10 - (x+2)^2
7x+10 - (x^2 + 2x + 4)
7x+ 10 - x^2 - 2x - 4
5x + 6 - x^2
then if u have to find the value of x then put the value of a = 1,b = 5,c = 6 in quadratic formula (-b + under root b^2 - 4ac / 2a) or (- b - under root b^2 - 4ac / 2a) it will gives the value of x...
HOPE it u..!!
edit - do let me knw that it's right or not..!!
f(5) means to replace x in the equation with 5 then solve.
f(x) = x^2 +2x
f(5) = 5^2 + 2(5)
f(5) = 25 +10
f(5) = 35
The answer is D)35
Well... the segment FG = 4x + 3, the segment GH = 7x - 12, now, the
segment FH = FG + GH, those two fellows added up, and we know that FG and GH are both equal halves because G is the midpoint.
thus, FG = GH
or
and fairly sure, you know how much that is.
