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marissa [1.9K]
3 years ago
5

What is the least common denominator of 1/4, 3/7, 1/11

Mathematics
1 answer:
inna [77]3 years ago
6 0
Alright. One way you can do this is to list multiples of each denominator:

1/4:
4, 8, 12, 16, 20, 24, 28, 32, 36...... and so on

3/7:
7, 14, 21, 28, 35, 42, 49, 57, 63......

1/11;
11, 22, 33, 44, 55, 66, 77, 88......

Keep going until you see the least common denominator!

Now an easier way to do this is by multiplying all of the numbers in the denominator then get the factors:

4*7*11 = 308

And since those are not divisible by a whole number (besides 4 but 308 won't be divisible by 2*7*11)

Therefore 308 is the least common denominator.
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Solve by factorization<br> 2x^2 + 3x -20 = 0
saul85 [17]

Answer:

x=2.5 or x=-4

Step-by-step explanation:

factorisation= factors:1, 2, 4, 5, 10, 20 (only the positive factors)

We will use the factors 4 and 5.

=(2x-5)(x+4)=0

2x-5=0   || x+4=0

2x=+5      || x=-4

x=2.5  or x=-4

4 0
3 years ago
Read 2 more answers
Write the equation of the line graphed below in Slope-Intercept form. State the slope and y-intercept.
Viefleur [7K]

Answer:

Equation: Y = -x + -3

Slope: -x

Y-intercept: -3

8 0
3 years ago
A cake recipe says to bake the cake until the center is 180 degrees F, then let the cake cool to 110 degrees F. The table shows
jeka94

Answer:

Check the explanation

Step-by-step explanation:

a) The following exponential model would fit the given dataset : \small y = 129.122 \times (0.9742)^x

b) To cool down to 110 degrees, it would take approximately 7.3 minutes based on the above model.

4 0
3 years ago
Find the distance between the points ?<br><br> ​
tatuchka [14]

Answer:

4

Step-by-step explanation:

The distance between the two points is (-1,-4) - (-5,-4)

5 0
3 years ago
(y - 2)2 = y2 – 6y + 4<br> Is this statement true or false?
trasher [3.6K]
<h3>Answer: False</h3>

==============================================

Explanation:

I'm assuming you meant to type out

(y-2)^2 = y^2-6y+4

This equation is not true for all real numbers because the left hand side expands out like so

(y-2)^2

(y-2)(y-2)

x(y-2) .... let x = y-2

xy-2x

y(x)-2(x)

y(y-2)-2(y-2) ... replace x with y-2

y^2-2y-2y+4

y^2-4y+4

So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4

--------------------------

Another approach is to pick some y value such as y = 2 to find that

(y-2)^2 = y^2-6y+4

(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2

0^2 = 2^2 - 6(2) + 4

0 = 4 - 6(2) + 4

0 = 4 - 12 + 4

0 = -4

We get a false statement. This is one counterexample showing the given equation is not true for all values of y.

6 0
3 years ago
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