Hello,
This is not an equation but an expression.
We must see the sign "=" in a equation!
Netherless,
12x^4-27x^3+6x²=3x²(4x²-9x+2)=3x²(4x²-8x-x+2)
=3x²(4x(x-2)-1(x-2))
=3x²(x-2)(4x-1)
Answer
Area of the rug is 64 in^2
Answer:
The area of the sector BOC is A' = 31.4
Step-by-step explanation:
Radius of the circle = 10 cm = 0.1 m
Angle of sector = 36°
Area of the circle A =
A = 3.14 × = 0.0314
Now area of the sector BOC is
A' = 0.00314 = 31.4
Therefore the area of the sector BOC is A' = 31.4
Answer:
imma Pipinow a ple roblx idunno wat da answer is am pram pelepens
a). Area = (length) (width)
= (60 ft) (√18 ft)
= (60 √18) ft²
= 60 √(9 · 2) ft²
= 60 (3) √2 ft²
= 180 √2 ft² (about 254.6 ft²)
b). Volume = (length) (width) (height)
= (60 ft) (√18 ft) (√10 ft)
= 60 √(180) ft³
= 60 √(4 · 9 · 5) ft³
= 60 (2) (3) √5 ft³
= 360 √5 ft³ (about 805 ft³)