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PilotLPTM [1.2K]
4 years ago
9

Solve for e. g/e^2 - r = m - y

Mathematics
1 answer:
vesna_86 [32]4 years ago
5 0

\bf \cfrac{g}{e^2}-r=m-y\implies \cfrac{g}{e^2}=m-y+r\implies g=e^2(m-y+r) \\\\\\ \cfrac{g}{m-y+r}=e^2\implies \pm\sqrt{\cfrac{g}{m-y+r}}=e

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Please help me get an answer
balandron [24]
The y intercept in the scatter plot means that at 0 years working, you will get paid $8 per hr. The y intercept can be represented by the ordered pair (0,8). The independent variable is the # of years and the dependent variable is pay per hour.

Hope this helped :)
3 0
3 years ago
3 log 2x=4 Please solve
Leno4ka [110]

3 log 2x=4\ /:3\\log2x=\frac{4}{3}\\10^{\frac{4}{3}}=2x\ /:2\\x=\frac{10\sqrt[3]{10} }{2}\\x=5\sqrt[3]{10}

6 0
3 years ago
Which statements accurately describe the function f(x) = 3(StartRoot 18 EndRoot) Superscript x? Select three options. The domain
Studentka2010 [4]

Answer:

The domain is all real numbers.

The initial value is 3

The simplified base is 9\sqrt{2}

Step-by-step explanation:

The given function is f(x)=3(\sqrt{18})^x.

To find the initial value, we put x=0 into the function:  

f(0)=3(\sqrt{18})^0.

f(0)=3(1)=3.

The initial value is actually 3.

The given function is an exponential function, therefore the domain is all real numbers.

The range of this function refers to all values of y for which the function is defined.

The line y=0, is the horizontal asymptote.

The range is y\:>\:0

The simplified base is 3\sqrt{18}=3\sqrt{9\times2}.

3\sqrt{18}=3\sqrt{9}\times\sqrt{2}

3\sqrt{18}=3\times3\times\sqrt{2}

3\sqrt{18}=9\sqrt{2}

4 0
3 years ago
Read 2 more answers
Anyone know this one?
9966 [12]

Answer:

(-3, 5), (1, 4), (-2, 3), and (0, 2).

Step-by-step explanation:

When a function is inverted, the x-values become y-values, and the y-values become x-values.

The ordered pairs for the function are (5, -3), (4, 1), (3, -2), and (2, 0).

After inversion, the ordered pairs will be (-3, 5), (1, 4), (-2, 3), and (0, 2).

Hope this helps!

7 0
3 years ago
A 50-gallon tank is filled with a 40% ethanol solution. How much solution should be drained but and replaced with an 80% ethanol
DIA [1.3K]

How do you create your equations when working on a mixture word problem?

Let's try to think about the general form of a word problem involving mixtures.

In general, we have the following scenario:

a merchant sells two kinds of products (coffee, sweets, etc).

we know the unit prices for both kinds of products and for the final mixture

p

1

US dollars per pound for the first kind of product,

p

2

US dollars per pound for the second kind of product

p

m

US dollars per pound for the mixture

we know the total quantity formed by the mixture of the two products (

q

pounds)

we have to find out the quantities of each product needed to form the mixture

(here we have the variables:

x

denoting the quantity of the first kind of product and

y

denoting the quantity of the second kind of product)

Now, we have sufficient information to work out the equations.

First, we know that the sum of the two quantities is

q

pounds, which gives us the first equation:

x

+

y

=

q

Second, we know that the sale price is the product of quantity and unit price, which gives us the second equation:

p

1

x

+

p

2

y

=

p

m

⋅

q

Now, we have a system of two linear equations that can be easily solved by substitution.

3 0
3 years ago
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