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PilotLPTM [1.2K]
3 years ago
9

Solve for e. g/e^2 - r = m - y

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0

\bf \cfrac{g}{e^2}-r=m-y\implies \cfrac{g}{e^2}=m-y+r\implies g=e^2(m-y+r) \\\\\\ \cfrac{g}{m-y+r}=e^2\implies \pm\sqrt{\cfrac{g}{m-y+r}}=e

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Answer:

1. When we reflect the shape I along X axis it will take the shape I in first quadrant, and then if we rotate the shape I by 90° clockwise, it will take the shape again in second quadrant . So we are not getting shape II. This Option is Incorrect.

2. Second Option is correct , because by reflecting the shape I across  X axis and then by 90° counterclockwise rotation will take the Shape I in second quadrant ,where we are getting shape II.

3. a reflection of shape I across the y-axis followed by a 90° counterclockwise rotation about the origin takes the shape I in fourth Quadrant. →→ Incorrect option.

4. This option is correct, because after reflecting the shape through Y axis ,and then rotating the shape through an angle of 90° in clockwise direction takes it in second quadrant.

5. A reflection of shape I across the x-axis followed by a 180° rotation about the origin takes the shape I in third quadrant.→→Incorrect option

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3 years ago
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I need help with this question:
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Answer:

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3 years ago
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