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2 years ago

Solve open parentheses square root of 6 close parentheses to the 8 x power = 216x−3.

Mathematics

2 answers:

Inessa05 [86]2 years ago

6 0

Answer:

-9

Step-by-step explanation:

ololo11 [35]2 years ago

4 0

We can make the base of the equation same on both the sides and then equate the exponents to get the answer as shown below:

$(\sqrt{6})^{8x}=(216)^{x-3} \\ \\ (\sqrt{6})^{8x}=(6^{3})^{x-3} \\ \\ (6^{\frac{1}{2}}) ^{8x}=(6)^{3x-9} \\ \\ (6)^{4x} =(6)^{3x-9} \\ \\ 4x=3x-9\\ \\ 4x-3x=-9\\ \\ x=-9$

Therefore, first option gives the correct answer

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A region is bounded by y=e−3x, the x-axis, the y-axis and the line x = 3. If the region is the base of a solid such that each cr

grigory [225]

Answer:

0.333 $\pi$ units³

Step-by-step explanation:

Think process:

The equation is given as y = $e^{-3x}$

Let, y = f (x)

Therefore, $f (x) = e^{-3x}$

We know that the limits are y-axis and x= 3

Y-axis: x= 0

then limits are given as x= 0 and x = 3

Integrating gives:

$\int\limits^3_0 {e^{-3x} } \, dx$ = $\frac{-1}{3}e^{-3x}$ + C

calculating from x= 0 to x = 3, we know volume is given by $\pi \int\limits^a_b {f(x)} \, dx$

= $\pi$ [ $\frac{-1}{3} e^{-9} - (\frac{-1}{3} e^{0})$ ]

= $\pi$ [0.000041136 + 1/3]

= 0.333 $\pi$ units³

8 0

2 years ago

How do you do this question?????

aleksklad [387]

It would 9 : 12 : 24

24 ÷ 8 = 3

4 • 3 = 12

3 • 3 = 9

3 0

2 years ago

Solve for t.

iVinArrow [24]

Answer:

4t - 3 > 37t - 50

Step-by-step explanation:

Step 1: 4t - 3 > 37t - 50

-4t -4t

-3 > 33t - 50

+50 + 50

47 > 33t

33 33

t < 47/33

3 0

2 years ago

Need help for this please

Ksju [112]

Answer:

The area of the circle is approximately 154 square meters

Step-by-step explanation:

Area of a circle formula: $A = \pi r^{2}$

given:

- diameter = 14m

- pi = 22/7

$radius (r) = diameter/2 = 14/2 = 7\\A = 22/7*(7)^2\\A = 22/7*(49)\\A = 154$

8 0

1 year ago

What are the coordinates of the center of the ellipse shown below?

photoshop1234 [79]

Answer:

Option D (7, -3)

Step-by-step explanation:

We know that the general equation of an ellipse has the form:

$\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1$

Where the point (h, k) are the coordinates of the center of the ellipse

In this case the equation of the ellipse is:

$\frac{(x-7)^2}{4} + \frac{(y+3)^2}{16} = 1$

Then

$h=7\\\\k = -3$

So The coordinates of the center of the ellipse are (7, -3)

8 0

2 years ago

Read 2 more answers