Answer:
The 1st Blank is: A pure substance, or simply a substance
The 2nd blank on the left is: Elements
The 3rd blank on the right is: Compounds
The 4th blank which is the second middle one is: A mixture
The 5th blank which is the bottom left one is: Heterogeneous mixture
The 6th blank which is the last one on the bottom right is: Homogeneous mixture
Look at the step-by-step explanation if you get confused at the bottom.
Step-by-step explanation:
The 1st Blank: I would just put a pure substance.
The 2nd blank on the left: They are three characteristics of elements but just put elements.
The 3rd blank on the right: They are three characteristics of compounds but just put compounds.
The 4th blank which is the second middle one is: The characteristics of a mixture but just put a mixture.
The 5th blank which is the bottom left one: Are the characteristics of a heterogeneous mixture but just put heterogeneous mixture.
The 6th blank which is the last one on the bottom right: Are the characteristics of a homogeneous mixture but just put homogeneous mixture.
Answer:c,d,f I think
Step-by-step explanation:
In this question, we have to write the set of points from -6 to 3 but excluding -2 and 3 as a union of intervals .
For union, we use U.
For the points that we have to exclude , we put parenthesis on there side that is ().
Therefore the required interval form is

As we see that () are used with -2 and 3 . And that's the required interval form .
Answers:
10.) 
9.) 
8.) 
7.) 
6.) 
Step-by-step explanations:
10.) 
9.) ![\displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5Csqrt%5B3%5D%7B135%7D%7D%7B%5Csqrt%5B3%5D%7B40%7D%7D%20%5Chookrightarrow%20%5Csqrt%5B3%5D%7B3%5Cfrac%7B3%7D%7B8%7D%7D%20%5Chookrightarrow%20%5Cfrac%7B3%5Csqrt%5B3%5D%7B5%7D%7D%7B2%5Csqrt%5B3%5D%7B5%7D%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7B1%5Cfrac%7B1%7D%7B2%7D%7D)
8.) ![\displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%5Csqrt%5B4%5D%7B162%7D%7D%7B%5Csqrt%5B4%5D%7B32%7D%7D%20%5Chookrightarrow%20%5Csqrt%5B4%5D%7B5%5Cfrac%7B1%7D%7B16%7D%7D%20%5Chookrightarrow%20%5Cfrac%7B%5Cpm%7B3%5Csqrt%5B4%5D%7B2%7D%7D%7D%7B%5Cpm%7B2%5Csqrt%5B4%5D%7B2%7D%7D%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7B%5Cpm%7B1%5Cfrac%7B1%7D%7B2%7D%7D%7D)
7.) 
6.) 
I am joyous to assist you at any time.
Do you mean 6 to the 5th power. or is there another 6, if so then it would be 6 to the 6th power.