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dimaraw [331]
2 years ago
9

Tim x: 3x(x-2) + 2(2-x)=0

Mathematics
1 answer:
olganol [36]2 years ago
6 0

Answer:

Assuming this is the full problem.

3x^2-8x+4

Step-by-step explanation:

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Please help!!! MAX POINTS I CAN DO i put it in math because i trust the math people more
valkas [14]

Answer:

The 1st Blank is: A pure substance, or simply a substance

The 2nd blank on the left is: Elements

The 3rd blank on the right is: Compounds

The 4th blank which is the second middle one is: A mixture

The 5th blank which is the bottom left one is: Heterogeneous mixture

The 6th blank which is the last one on the bottom right is: Homogeneous mixture

Look at the step-by-step explanation if you get confused at the bottom.


Step-by-step explanation:

The 1st Blank: I would just put a pure substance.

The 2nd blank on the left: They are three characteristics of elements but just put elements.

The 3rd blank on the right: They are three characteristics of compounds but just put compounds.

The 4th blank which is the second middle one is: The characteristics of a mixture but just put a mixture.

The 5th blank which is the bottom left one: Are the characteristics of a heterogeneous mixture but just put heterogeneous mixture.

The 6th blank which is the last one on the bottom right: Are the characteristics of a homogeneous mixture but just put homogeneous mixture.


3 0
2 years ago
Read 2 more answers
Which set of points on the graph represents equivalent ratios?
Elenna [48]

Answer:c,d,f I think

Step-by-step explanation:

8 0
2 years ago
Write the set of points from −6−6 to 33 but excluding −2−2 and 33 as a union of intervals:
Softa [21]

In this question, we have to write the set of points from -6 to 3 but excluding -2 and 3 as a union of intervals .

For union, we use U.

For the points that we have to exclude , we put parenthesis on there side  that is  ().

Therefore the required interval form is

[-6,-2)U(-2,3)

As we see that () are used with -2 and 3 . And that's the required interval form .

5 0
3 years ago
6-10 divide, another onee thank you!!​
eduard

Answers:

10.) \displaystyle \pm{5}

9.) \displaystyle 1\frac{1}{2}

8.) \displaystyle \pm{1\frac{1}{2}}

7.) \displaystyle \pm{1\frac{1}{2}}

6.) \displaystyle \pm{\frac{1}{2}}

Step-by-step explanations:

10.) \displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}

9.) \displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}

8.) \displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

7.) \displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

6.) \displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}

I am joyous to assist you at any time.

5 0
2 years ago
The series 6 + 6 + 6+ 6 + 6 +
Alexandra [31]
Do you mean 6 to the 5th power. or is there another 6, if so then it would be 6 to the 6th power.
6 0
2 years ago
Read 2 more answers
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