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3 years ago

15

Lola bought x pencils that cost $0.25 each and y erasers that cost $0.50. She spent less than $3. Which graph represents Lola’s

purchase?

1 answer:

Furkat [3]3 years ago

6 0

One question: Where is the graphs?

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The length of a rectangle is 8 feet more than its width. If the width is increased by 4 feet and the length is decreased by 5 fe

alexgriva [62]

Let the width be x.

Length is 8 feet more than width. Length = x + 8

Area = x(x + 8)

width increased by 4, that is, (x + 4)
Length decreased by 5, (x + 8 - 5) = (x + 3)

Area = (x + 4)(x +3)

Area remains the same

x(x + 8) = (x+4)(x +3)

x² + 8x = x(x +3) + 4(x +3)

x² + 8x = x² +3x + 4x +12

x² + 8x = x² +7x +12 Eliminate x² from both sides

8x = 7x + 12

8x - 7x = 12

x = 12

Dimensions of original rectangle : x, x + 8

12, 12 +8 = 12, 20

Original rectangle is 20 feet by 12 feet

5 0

3 years ago

Read 2 more answers

Help could you explain step by step?

mel-nik [20]

Answer:

x = 2 , y = 11

Step-by-step explanation:

the diagonals of a parallelogram bisect each other , then

PT = TR , that is

y = 5x + 1 → (1)

QT = TS , that is

2y = 6x + 10 → (2)

substitute y = 5x + 1 into (2)

2(5x + 1) = 6x + 10

10x + 2 = 6x + 10 ( subtract 6x from both sides )

4x + 2 = 10 ( subtract 2 from both sides )

4x = 8 ( divide both sides by 4 )

x = 2

substitute x = 2 into either of the 2 equations for corresponding value of y

substituting into (1)

y = 5(2) + 1 = 10 + 1 = 11

6 0

2 years ago

Read 2 more answers

Which table has a constant of proportionality between yyy and xxx of 101010?

Gnesinka [82]

Answer:

Only table C shows proportional relationship

Step by Step Explanation:

Given

Tables A, B an C

Required

Which table shows proportional relationship?

In table A .

x = 2 and y = 20

k = 20/2

k = 10

Also, x = 12, y = 132

k =. 132/12.

k = 11

Both values of k are not equal.

Hence, the table is not proportional

In table B

x = 5 and y = 20

k = 20/5

k = 4

Also, x = 7, y = 30

k =. 30/7

k = 4.29

Both values of k are not equal.

Hence, the table is not proportional

In table C

x = 9 and y = 90

k = 90/9

k = 10

Also, x = 14, y = 140

k =. 140/14

k = 10

Also, x = 24, y = 240

k =. 240/24

k = 10

All values of k are equal.

Hence, the table is proportional

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3 years ago

How do you like math plz explain

Digiron [165]

I like math because it gets me thinking a lot. math helps me in the world because we need to know how to do math in order to go shopping or we will not give the cashier the correct amount or maybe you will give them an extra amount of money because you can't do math.

6 0

3 years ago

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A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

<em>Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom</em>

<em>The null hypothesis is accepted . </em>

<em>Assume the population variances are approximately the same</em>

<u><em>Step-by-step explanation:</em></u>

<u>Explanation</u>:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

<em>The first sample size 'n₁'= 20</em>

<em>mean of the first sample 'x₁⁻'= 17.53 pounds</em>

<em>standard deviation of first sample S₁ = 3.2 pounds</em>

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

<em>The second sample size n₂ = 24</em>

<em>mean of the second sample "x₂⁻"= 14.89 pounds</em>

<em>standard deviation of second sample S₂ = 2.7 poun</em>ds

<u><em>Null hypothesis</em></u><u>:-</u><u><em>H₀</em></u><em>: The Population Variance are approximately same</em>

<u><em>Alternatively hypothesis</em></u><em>: H₁:The Population Variance are approximately same</em>

<em>Level of significance ∝ =0.05</em>

<em>Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42</em>

<em>Test statistic :-</em>

<em> </em> $t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

<em> where </em> $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

<em> substitute values and we get S² = 40.988</em>

<em> </em> $t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$ <em></em>

<em> </em> t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

<u><em>Conclusion</em></u>:-

<em>The null hypothesis is accepted </em>

<em>Assume the population variances are approximately the same.</em>

<em> </em>

<em> </em>

<em> </em>

6 0

3 years ago