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lapo4ka [179]
4 years ago
3

What is the solution set of the equation: 7q^2 - 28 = 0

Mathematics
1 answer:
Romashka [77]4 years ago
8 0
7q² - 28 = 0
     + 28 + 28
       7q² = 28
         7      7
         q² = 4
          q = ±4
          q = 4    or    q = -4

Solution Set: {±4} and {q|q = 4 or q = -4}

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Arm span is the physical measurement of the length of an individual's arms from fingertip to fingertip. A man’s arm span is appr
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Answer:

The 99th percentile for a man’s arm span is 80.47 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 70, \sigma = 4.5

99th percentile

X when Z has a pvalue of 0.99. So X when Z = 2.327.

Z = \frac{X - \mu}{\sigma}

2.327 = \frac{X - 70}{4.5}

X - 70 = 2.327*4.5

X = 80.47

The 99th percentile for a man’s arm span is 80.47 inches.

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Bailey was building a pond. The pond held 40.5 gallons of water. She had already put 27.9 gallons of water in it. Bailey said sh
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B since it's rounded to a closer than C
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PLEASE HELPPP, its timed. NO BOTS please i want serious answers.
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CDAB

4.2 (convert to frac on ur own)

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3 years ago
Use Cramer’s Rule to solve system of equation.
alisha [4.7K]

\left\{\begin{array}{ccc}5x+2y=4\\3x+4y+2z=6\\7x+3y+4z=29\end{array}\right\\\\A=\left[\begin{array}{ccc}5&2&0\\3&4&2\\7&3&4\end{array}\right]\\\\\det A=5\cdot4\cdot4+3\cdot3\cdot0+2\cdot2\cdot7-7\cdot4\cdot0-3\cdot2\cdot5-3\cdot2\cdot4=54\\W_x=\left[\begin{array}{ccc}4&2&0\\6&4&2\\29&3&4\end{array}\right]\\\det W_x=4\cdot4\cdot4+2\cdot2\cdot29+6\cdot3\cdot0-29\cdot4\cdot0-3\cdot2\cdot4-6\cdot2\cdot4=108

W_y=\left[\begin{array}{ccc}5&4&0\\3&6&2\\7&29&4\end{array}\right]\\\det W_y=5\cdot6\cdot4+3\cdot29\cdot0+4\cdot2\cdot7-7\cdot6\cdot0-29\cdot2\cdot5-3\cdot4\cdot4=-162\\W_z=\left[\begin{array}{ccc}5&2&4\\3&4&6\\7&3&29\end{array}\right]\\\det W_z=5\cdot4\cdot29+3\cdot3\cdot4+6\cdot2\cdot7-7\cdot4\cdot4-3\cdot6\cdot5-3\cdot2\cdot29=324\\\\x=\dfrac{\det W_x}{\det A}=\dfrac{108}{54}=2\\\\y=\dfrac{\det W_y}{\det A}=\dfrac{-62}{54}=-3\\\\z=\dfrac{\det W_z}{\det A}=\dfrac{324}{54}=6

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Solve the formula Ax + By = C for A
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Ax+By=C
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