Solve for x: 4 over x equals 5 over 10

Mathematics

2 answers:

julsineya [31]3 years ago

8 0

Answer:

x = 8,

Step-by-step explanation:

$\displaystyle \frac{4}{x} = \frac{5}{10}$ .

$x \ne 0$ for it is a denominator. Multiply both sides with the product of the two denominators: $10\;x$ :

$\displaystyle \frac{4}{x}\cdot (10\; x) = \frac{5}{10}\cdot (10\;x)$ .

$40 = 5\; x$ .

Multiply both sides by one over the coefficient of x:

$\displaystyle \frac{1}{5} \times 40 = \frac{1}{5}\times 5\; x$ .

$x = 8$ .

laila [671]3 years ago

5 0

Answer : Answer is 8

Step-by-step explanation:

Took the test

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Answer:

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Step-by-step explanation:

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Range of f: "What values of f(x) can we get out of the function?" From the graph we see we can get any real number greater than 0 out of the function by choosing a suitable x-value in the domain. The range is therefore $(0, \infty)$ .

Continuity: Since the graph is one, unbroken curve (i.e. a curve that can be drawn in one movement without taking your pen off the paper). We see that "roughly speaking" the function is continuous.

Increasing or decreasing behaviour: For all x in the domain, as x increases, f(x) decreases. This means the function exhibits decreasing behaviour.

Symmetry: It is clear to see the graph of f(x) has no symmetry.

Boundedness: Looking at the graph we see it is unbounded above as when we choose negative values, the graph of f(x) explodes upwards exponentially. Choose a value of x, plug it in, next choose (x-1), plug this in and we observe $f(x-1) > f(x)$ for all x in the domain.

The function is however bounded below by 0: no value of x in the domain exists which satisfies $f(x) < 0$ .

Extrema: As far as I can tell, there are no turning points on the curve. (Is this what you mean by extrema?)

Asymptotes: Contrary to the curve's appearance, there are no vertical asymtotes for this curve. The negative-x portion of the curve is just growing so quickly it appears to look like an asymptote. There is a value of f(x) for all x<0. There is however a horizontal asymtote: $y=0$ .