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nexus9112 [7]
3 years ago
12

I have 3 Algebra questions can anyone help?

Mathematics
1 answer:
Kisachek [45]3 years ago
4 0

1.  9x^2+4x-8

2. 6x^3+16x^2+3x+8

3. 5x^4-27x^3-14x^2+24x

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After sales tax, an $81 cell phone costs $84.24. What is the sales tax percentage?​
Igoryamba

Answer:

4% sales tax

Step-by-step explanation:

Take the original costs and subtract it from the price after sales tax.

$84.24-$81= $3.24

Divide 3.24 by 81

this gives you .04, now either multiply by 100 or move the decimal two places to the right to convert the decimal to a percentage.

4 0
2 years ago
How are √25 and √-25 different in the terms of a solution for both? *
Tanya [424]

Answer:

For \sqrt{25} it will be plus or minus \sqrt{5}

For \sqrt{-25} it will be plus or minus \sqrt{5i}

Step-by-step explanation:

Well for \sqrt{-25} it will be 5i

Because i = -1  

6 0
3 years ago
Solve for x. x - 2(2 - 3/2 x) = 2(4 - x) + 1
STALIN [3.7K]

Answer:

x = 13/6

Step-by-step explanation:

We are the following expression;

       x - 2(2 - (3/2)*x) = 2(4 - x) + 1

       x - (4 - 3*x) = 8 - 2*x + 1

       x - 4 + 3*x = 8 - 2*x + 1

         4*x + 2*x = 9 + 4

             6*x = 13

              x = 13/6

8 0
3 years ago
How do you convert 10um
Lerok [7]

Answer:

10 \times  {10}^{ - 6 } = .000001

3 0
3 years ago
A cube of sides 10cm was cut across to obtain a prism. Calculate the surface area of the prism and the volume of the prism
hodyreva [135]

Answer:

Part A

The volume of the triangular prism is 500 cm³

Part B

The total surface area of the prism is approximately 441.42 cm²

Step-by-step explanation:

The given details are;

The dimensions of the side length of the cube, s = 10 cm

The shape the cube was cut across to obtain = A prism

Part A

Whereby the prism obtained is a triangular prism, we have;

The cube can be cut in half to form a triangular prism

The volume of each triangular prism obtained = (1/2) × The volume of the cube

∴ The volume of the triangular prism = (1/2) × (10 cm)³ = 500 cm³

Part B

The height of the prism, h = 10 cm × sin(45°) = 5·√2 cm = (1/2) × The base width of the prism

The triangular cross sectional area of the prism, A₁ = 5·√2 × 5·√2 = 50

The square cross sectional area, A₂  = 10 × 10 = 100

The cross sectional area of the base, A₃ = 10·√2 × 10 = 100·√2

The total surface area of the prism, A = 2·A₁ + 2·A₂ + A₃

∴ A = 2×50 + 2×100 + 100·√2 = 300 + 100·√2 ≈ 441.42

The total surface area of the prism, A ≈ 441.42 cm²

4 0
3 years ago
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