dentify the horizontal asymptote of f(x) = quantity x squared plus 5 x minus 3 over quantity 4 x minus 1.
1 answer:
Answer:
Horizontal asymptote does not exist
Step-by-step explanation:
we are given
We can see that
degree of numerator is 2
and degree of denominator is 1
So, degree of numerator is greater than degree of denominator
So, in such cases , horizontal asymptote does not exist
So,
Horizontal asymptote does not exist
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Answer:
y = x + 7
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = (2, 8) and (x₂, y₂ ) = (10,12) ← 2 ordered pairs from the table
m = =
=
y = x + c ← is the partial equation
to find c substitute any ordered pair into the partial equation
using (6, 10 ), then
10 = 3 + c ⇒ c = 10 - 3 = 7
y = x + 7 ← linear equation