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3 years ago

5

Atoms contain subatomic particles called protons and neutrons. When these protons and neutrons split, a lot of energy is release

d what kind of energy is this?

2 answers:

GarryVolchara [31]3 years ago

8 0

I think it is kinetic energy or atomic.

Troyanec [42]3 years ago

4 0

Answer: Necular

Explanation:

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A 500 N force is applied to an object accelerating at 25 m/s^2.<br> what is the mass of the object?

krok68 [10]

Answer:

there are go fella hope u understood

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3 years ago

Jogger A has a mass m and a speed v, jogger B has a mass m/2 and a speed 3v, jogger C has a mass 3m and a speed v/2, and jogger

finlep [7]

Answer: B>A=D>C

Explanation:

Kinetic Energy is the product of mass and square of the velocity

For Jogger A

$K.E._a=\frac{1}{2}mv^2$

For Jogger B

$K.E._b=\frac{1}{2}\times\frac{m}{2}\times(3v)^2=\frac{9}{4}mv^2\\K.E._b=2.25mv^2$

For Jogger C

$K.E._c=\frac{1}{2}\times3m\times(\frac{v}{2})^2=\frac{3}{8}mv^2\\K.E._c=0.375mv^2$

For Jogger D

$K.E._d=\frac{1}{2}\times4m\times(\frac{v}{2})^2=\frac{1}{2}mv^2$

Kinetic Energy of Joggers in increasing order

B>A=D>C

8 0

3 years ago

Does air resistance affect the motion of a falling object differently when the initial velocity of the object is greater?

DIA [1.3K]

Yes. Even greater. Air resistance or drag becomes harder the faster an object goes. This is why when cars reach their max speed they don't accelerate as fast, because they are pushing harder against the wind. If I take a tennis ball and shoot it down a bottomless pit, a 400 kph, the drag will slow the ball down till it reaches terminal velocity.

4 0

3 years ago

Read 2 more answers

A bungee jumper attains a speed of 30 m/s just as the bungee cord begins to stretch. If the period of stretch is 2 s while comin

Bogdan [553]

Answer: $1.53g$

Explanation:

average deceleration= ?

inial velocity: $u=0$

final velocity: $v=30m/s$

time: $t=2seconds$

The first law of kinematics :

$v=u+at$

find a the subject of the formula

$a=v-u/ t$

$a=\frac{0-30} 2$

$a=-30/2$

$a=-15m/s^{2}$

The deceleration about g(acceleration due to gravity) will be:

$15/9.8$

$1.53g$

4 0

3 years ago

Write the nuclear reaction equation for the beta decay of Iodine-131

den301095 [7]

Answer:

$_{53}^{131}I \rightarrow _{54}^{131}Xe + e + \bar{\nu}$

Explanation:

In a beta (minus) decay, a neutron in a nucleus turns into a proton, emitting a fast-moving electron (called beta particle) alongside with an antineutrino.

The general equation for a beta decay is:

$^A_Z X \rightarrow _{Z+1}^AY+^0_{-1}e+ ^0_0\bar{\nu}$ (1)

where

X is the original nucleus

Y is the daughter nucleus

e is the electron

$\bar{\nu}$ is the antineutrino

We observe that:

The mass number (A), which is the sum of protons and neutrons in the nucleus, remains the same in the decay
The atomic number (Z), which is the number of protons in the nucleus, increases by 1 unit

In this problem, the original nucles that we are considering is iodine-131, which is

$_{53}^{131}I$

where

Z = 53 (atomic number of iodine)

A = 131 (mass number)

Using the rule for the general equation (1), the dauther nucleus must have same mass number (131) and atomic number increased by 1 (54, which corresponds to Xenon, Xe), therefore the equation will be:

$_{53}^{131}I \rightarrow _{54}^{131}Xe + e + \bar{\nu}$

7 0

3 years ago

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