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ivolga24 [154]
3 years ago
12

5. How much does a 20 m x 10 m x 8 m swimming pool filled with water weigh? Assume that water has a density of 62 kg/m².​

Physics
2 answers:
Licemer1 [7]3 years ago
6 0

Answer:

fxhehjejejkwkwkkwkwkqklwkjsnenrnkeke

scoray [572]3 years ago
3 0

Answer:

99,200kg

Explanation:

density= mass/volume

given d-62kg/m*3

v=20×10×8. =1600

m=x

1600×62=99,200kg

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A ball is dropped from a height of 80m. The time, in seconds, it takes to reach the ground is:__________.
Aleonysh [2.5K]

Answer:

4.04 s

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h = vi + 1/2 a t ^2

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80 = 4.905 t^2

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3 years ago
A child bouncing a ball. Which law of motion does the situation describe?​
vlada-n [284]
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Suppose you are at the center of a large freely-rotating horizontal turntable in a carnival funhouse. As you crawl toward the ed
I am Lyosha [343]

Answer:

c. remains the same, but the RPMs decrease.

Explanation:

Because there aren't external torques on the system composed by the person and the turntable it follows that total angular momentum (I) is conserved, that means the total angular momentum is a constant:

\overrightarrow{L}=constant

The total angular momentum is the sum of the individual angular momenta, in our case we should sum the angular momentum of the turntable and the angular momentum of a point mass respect the center of the turntable (the person)

\overrightarrow{L_{turnatble}}+\overrightarrow{L_{person}}=constant (1)

The angular momentum of the turntable is:

\overrightarrow{L_{turnatble}}=I\overrightarrow{\omega} (2)

with I the moment of inertia and ω the angular velocity.

The angular momentum of the person respects the center of the turntable is:

\overrightarrow{L_{person}}=\overrightarrow{r}\times m\overrightarrow{v} (3)

with r the position of the person respects the center of the turntable, m the mass of the person and v the linear velocity

Using the fact v=\omega r:

\overrightarrow{L_{person}}=\overrightarrow{r}\times rm\overrightarrow{\omega}(3)

By (3) and (2) on (1) and working only the magnitudes (it's all that we need for this problem):

I\omega+r^{2}m\omega=constant

\omega(I+r^{2}m)=constant

Because the equality should be maintained, if we increase the distance between the person and the center of the turntable (r), the angular velocity should decrease to maintain the same constant value because I and m are constants, so the RPM's (unit of angular velocity) are going to decrease.

4 0
4 years ago
In the oscillating spring ball system, where is the velocity of the ball the greatest?
nlexa [21]

The speed of an object in a mass-spring system is given under the function

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v_{max}= A\sqrt{\frac{x}{m}}

So the correct answer is B.

6 0
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