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ivolga24 [154]
3 years ago
12

5. How much does a 20 m x 10 m x 8 m swimming pool filled with water weigh? Assume that water has a density of 62 kg/m².​

Physics
2 answers:
Licemer1 [7]3 years ago
6 0

Answer:

fxhehjejejkwkwkkwkwkqklwkjsnenrnkeke

scoray [572]3 years ago
3 0

Answer:

99,200kg

Explanation:

density= mass/volume

given d-62kg/m*3

v=20×10×8. =1600

m=x

1600×62=99,200kg

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adoni [48]
In order to gain their trust, so that in any situation in their lifes like any worry their in, they can trust their parents for solutions in this wore some moment.
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3 years ago
which of these statements best explains why the difference between summer and winter temperatures is greatet in Russia thanin FL
MaRussiya [10]
I don't know your statement, but one explanation for this is that Russia is mostly located on land, away from water and Florida is surrounded by water.

Water takes up the heat from the environment, so it has the effect of making the temperatures of objects around it milder: cooling down when hot, warming up when too cold.
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3 years ago
In an experiment designed to measure the Earth's magnetic field using the Hall effect, a copper bar 0.550 cm thick is positioned
motikmotik

Answer:

B= 4.197*10^-5T

Explanation:

We know that the magnetic Field of the Earth is 50\mu T, so the equation for

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\Delta V_H = \frac{IB}{nqt}

B=\frac{nqt\Delta V_h}{I}

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B= 0.00004197

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7 0
3 years ago
When an object is placed 110 cm from a diverging thin lens, its image is found to be 55 cm from the lens. The lens is removed, a
Kazeer [188]

Explanation:

Given that,

Object distance u= -110 cm

Image distance v= 55 cm

We need to calculate the focal length for diverging lens

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{-f}=\dfrac{1}{55}-\dfrac{1}{-110}

\dfrac{1}{f}=-\dfrac{3}{110}

f=-36.6\ cm

The focal length of the diverging lens is 36.6 cm.

Now given a thin lens with same magnitude of focal length 36.6 cm is replaced.    

Here, The object distance is again the same.

We need to calculate the image distance for converging lens

Using formula of lens

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Here, focal length is positive for converging lens

\dfrac{1}{v}=\dfrac{1}{36.6}-\dfrac{1}{110}

\dfrac{1}{v}=\dfrac{367}{20130}

v=54.85\ cm

The distance of the image is 54.85 cm from converging lens.

Hence, This is the required solution.

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3 years ago
A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the
leva [86]
Used an app called Mephyso to do the calculation.

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