Question

A bungee jumper attains a speed of 30 m/s just as the bungee cord begins to stretch. If the period of stretch is 2 s while coming to a halt, the jumper's average deceleration in g’s is about ______?

Answer 1

Answer:$1.53g$

Explanation:

average deceleration= ?

inial velocity: $u=0$

final velocity: $v=30m/s$

time: $t=2seconds$

The first law of kinematics :

$v=u+at$

find a the subject of the formula

$a=v-u/ t$

$a=\frac{0-30} 2$

$a=-30/2$

$a=-15m/s^{2}$

The deceleration about g(acceleration due to gravity) will be:

$15/9.8$

$1.53g$