Question

The lengths of the sides of a triangle are in the extended ratio 8 ​: 9 ​: 10. The perimeter of the triangle is 108 cm. What are the lengths of the​ sides?

Answer 1

Answer:

A(8)=32cm

B(9)=36cm

C(10)=40cm

Step-by-step explanation:

let 8:9:10=A:B:C

∑ratios=8+9+10=27

Therefore lengths or triangles:-

$Length A=\frac{A}{A+B+C}*108\\ =32\\Length B= \frac{B}{A+B+C}*108\\ =36\\Length C=\frac{C}{A+B+C}*108\\ =40$