Scott and Ariel want to make as much as snack mix as possible, but no more than 25 cups of mix. I they can use only full cups of
1 answer:
Answer:
hello your question has some missing parts attached below is the missing information
answer : Scott will make 5 snack mix without going over
Step-by-step explanation:
Given that:
Scott makes a snack mix with ; 2 cups of Almonds and 3 cups of raisins
= 5cups per snacks mix
Ariel makes a snack mix with : 3 cups of almonds and 5 cups of sunflower seeds = 8 cups per snack mix
<u>Now back to your question above</u>
Given that : No more than 25 full cups is required to make a snack mix
For Scott
= 25 / 5 = 5 snack mix ( No make overs )
For Ariel
= 25 / 8 = 3.125 snack mix ( there is a makeover of 0.125 )
Hence it can be said that Scott will make the most mix without going over
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Answer:
The first step is calculate the degrees of freedom, on this case:
Since is a one side right tailed test the p value would be:
And for this case we can conclude that:
And we will reject the null hypothesis at since
Step-by-step explanation:
Data given and notation
represent the mean height for the sample
represent the sample standard deviation
sample size
represent the value that we want to test
t would represent the statistic (variable of interest)
represent the p value for the test (variable of interest)
State the null and alternative hypotheses.
We need to conduct a hypothesis in order to check if the mean is higher than 15, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:
(1)
t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".
Calculate the statistic
For this case the statistic is given:
P-value
The first step is calculate the degrees of freedom, on this case:
Since is a one side right tailed test the p value would be:
And for this case we can conclude that:
And we will reject the null hypothesis at since