Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla = 
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.
Answer:
(m³/3 + 5m/2 + 3)pi
Step-by-step explanation:
pi integral [(f(x))² - (g(x))²]
Limits 0 to 1
pi × integral [(2+mx)² - (1-mx)²]
pi × integral[4 + 4mx + m²x² - 1 + 2mx - m²x²]
pi × integral [m²x² + 5mx + 3]
pi × [m²x³/3 + 5mx²/2 + 3x]
Upper limit - lower limit
pi × [m²/3 + 5m/2 + 3]
Verification:
m = 0
[pi × 2² × 1] - [pi × 1² × 1] = 3pi
[m³/3 + 5m/2 + 3]pi
m = 0
3pi
Answer:
10.5
Step-by-step explanation:
First, divide 6 by 2. You get 3, right? So now you know that you multiply by three to get the answer. 3.5 * 3 will equal 10.5
Cost per gallon is found by dividing the cost by the number of gallons.
$43.95/16.1 ≈ $2.7298137
Rounded to hundredths, this is $2.73.
Answer: 3(10x+5)
Step-by-step explanation: 30/3=10x + 15/3=5
