Complete Question
The length of the guy wire supporting a cell tower is 120 m. The guy wire is anchored to the ground at a distance of 80 m from the base of the tower to the nearest hundredth of a meter how tall is the tower?
Answer:
89.44m
Step-by-step explanation:
We solve this question using the Pythagoras Theorem
This is given as:
Hypotenuse² = Opposite ² + Adjacent ²
Hypotenuse = Length of the guy wire = 120m
Adjacent = Distance from the base of the tower = 80m
Opposite = Height of the building = x
Hence:
120² = x² + 80²
Collect like terms
x² = 120² - 80²
x = √120² - 80²
x = √(8000)
x = 89.4427191 m
Approximately the height of the tower is = 89.44m
I don’t know sorry but like how’s yoonbum doing? Also like wanna be friends?
Solution: The sum of probabilities of all the sample points must equal 1. And the probability of getting a head is equal to the probability of getting a tail. Therefore, the probability of each sample point (heads or tails) must be equal to 1/2. Let's repeat the experiment of Example 1, with a die instead of a coin.
<span>4000 feet is around 1.2192 km which is more than 1 km. So 4000 feet is longer.</span>