Answer:
1/18 hr per stretch
Step-by-step explanation:
total # of hrs / # of stretches
1/3 hr / 6 stretches = 1/18 hr per stretch
The answer is c b/c you multiply
Answer:
10x^3 + 6x^2 + 5x + 3
Step-by-step explanation:
F(x)=(5x+3)(2x^2+1)
= 5x*2x^2 + 5x*1 + 3*2x^2 + 3*1
= 10x^3 + 5x + 6x^2 + 3
= 10x^3 + 6x^2 + 5x + 3
Simplifying x2 + -8x = 20 Reorder the terms: -8x + x2 = 20 Solving -8x + x2 = 20 Solving for variable 'x'. Reorder the terms: -20 + -8x + x2 = 20 + -20 Combine like terms: 20 + -20 = 0 -20 + -8x + x2 = 0 Factor a trinomial. (-2 + -1x)(10 + -1x) = 0 Subproblem 1Set the factor '(-2 + -1x)' equal to zero and attempt to solve: Simplifying -2 + -1x = 0 Solving -2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1x = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1x = 0 + 2 -1x = 0 + 2 Combine like terms: 0 + 2 = 2 -1x = 2 Divide each side by '-1'. x = -2 Simplifying x = -2 Subproblem 2Set the factor '(10 + -1x)' equal to zero and attempt to solve: Simplifying 10 + -1x = 0 Solving 10 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1x = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1x = 0 + -10 -1x = 0 + -10 Combine like terms: 0 + -10 = -10 -1x = -10 Divide each side by '-1'. x = 10 Simplifying x = 10Solutionx = {-2, 10}
Answer:
There are 26 purple marbles in the bag.
Step-by-step explanation:
Firstly, you have to make an expression in terms of x where x represent red marbles. Given that the question says purple marbles is 2 more than 3 times the number of red marbles. So the expression is :
Let red marbles = x,
![purple = 2 + 3x](https://tex.z-dn.net/?f=purple%20%3D%202%20%2B%203x)
![red = x](https://tex.z-dn.net/?f=red%20%3D%20x)
Next, given that the total marbles in the bag is 34 so you have to add both marbles together and solve the value of x :
![2 + 3x + x = 34](https://tex.z-dn.net/?f=2%20%2B%203x%20%2B%20x%20%3D%2034)
![4x = 32](https://tex.z-dn.net/?f=4x%20%3D%2032)
![x = 32 \div 4](https://tex.z-dn.net/?f=x%20%3D%2032%20%5Cdiv%204)
![x = 8](https://tex.z-dn.net/?f=x%20%3D%208)
Lastly, you have to substitute the value of x into the expression of purple marbles :
Let x = 8,
![purpe = 2 + 3(8)](https://tex.z-dn.net/?f=purpe%20%3D%202%20%2B%203%288%29)
![purple = 26](https://tex.z-dn.net/?f=purple%20%3D%2026)