Which sequences are geometric? check all that apply.
1 answer:
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Answer:
y=7/3x²-13/3x+2
Step-by-step explanation:
<u>Determine the value of c:</u>
y=ax²+bx+c
2=a(0)²+b(0)+c
2=c
<u>Substitute (1,0) into the quadratic and create an equation with a and b:</u>
y=ax²+bx+2
0=a(1)²+b(1)+2
0=a+b+2
-2=a+b
<u>Do the same with (3,10) to get a second equation:</u>
y=ax²+bx+2
10=a(3)²+b(3)+2
10=9a+3b+2
8=9a+3b
<u>Set the two equations equal to each other and solve for a and b:</u>
-2=a+b
8=9a+3b
<u>Multiply first equation by 3 and eliminate b to find a:</u>
-6=3a+3b
- (8=9a+3b)
_______
-14=-6a
14/6=a
7/3=a
<u>Substitute 7/3=a into the first equation:</u>
-2=7/3+b
-2-(7/3)=b
-13/3=b
<u>Final equation:</u>
y=7/3x²-13/3x+2
See the graph for a visual representation
Answer:
0.03125 = 3.125% probability of obtaining 5 heads from 5 coin flips.
Step-by-step explanation:
For each coin flip, there are only two possible outcomes. Either it is heads, or it is tails. The probabilities for each flip are independent from each other. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
In this problem we have that:
For each coin toss, heads and tails are equally as likely, so
What is the probability of obtaining 5 heads from 5 coin flips?
This is P(X = 5) when n = 5.
So
0.03125 = 3.125% probability of obtaining 5 heads from 5 coin flips.