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almond37 [142]
3 years ago
7

What is the order of √5 , -0.1, -5/3 , 0.7, √2 from least to greatest?

Mathematics
1 answer:
Savatey [412]3 years ago
4 0
-5/3, -0.1, 0.7, sqrt2, sqrt5
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What is the slope of the line that passes through (-2,5) and (1,4)?<br> -3<br> -2<br> -1/3<br> 1/3
SIZIF [17.4K]

slope = m=(y2-y1)/(x2-x1)

m= (4-5)/(1-(-2))

m= -1/(1+2)

m=-1/3

Choice C

 

7 0
3 years ago
One zero of x3 – 3x2 – 6x + 8 = 0 is -2. What are the other zeros of the function?
hram777 [196]
Consider this solution, if it is possible, check the result:
1) if to divide polynomial 'x³-3x²-6x+8' on 'x+2' result is: x²-5x+4, then x³-3x²-6x+8=(x+2)(x²-5x+4);
2) x²-5x+4=(x-1)(x-4), then
3) x³-3x²-6x+8=(x+2)(x-1)(x-4).
4) zeros are: -2;1;4. Other zeros are: 1 and 4.
Answer: 1;4.
7 0
3 years ago
Someone help with this​
Fantom [35]

Step-by-step explanation:

6x2 - x + 3 - (-5x2 + 10x - 1)

6x2 - x + 3 + 5x2 - 10x + 1

Solving like terms

11x2 - 11x + 4

5 0
3 years ago
The number of customers waiting for gift-wrap service at a department store is an rv X with possible values 0, 1, 2, 3, 4 and co
julia-pushkina [17]

Answer:

P[X=3,Y=3] = 0.0416

Step-by-step explanation:

Solution:

- X is the RV denoting the no. of customers in line.

- Y is the sum of Customers C.

- Where no. of Customers C's to be summed is equal to the X value.

- Since both events are independent we have:

                         P[X=3,Y=3] = P[X=3]*P[Y=3/X=3]

              P[X=3].P[Y=3/X=3] = P[X=3]*P[C1+C2+C3=3/X=3]

        P[X=3]*P[C1+C2+C3=3/X=3] = P[X=3]*P[C1=1,C2=1,C3=1]        

              P[X=3]*P[C1=1,C2=1,C3=1]  = P[X=3]*(P[C=1]^3)

- Thus, we have:

                        P[X=3,Y=3] = P[X=3]*(P[C=1]^3) = 0.25*(0.55)^3

                        P[X=3,Y=3] = 0.0416

6 0
3 years ago
Rewrite each expression using the distributive property. Then combine like terms if possible. 2(x+4
Eduardwww [97]

Step-by-step explanation:

Step 1: Multiply the 2 with the X to get 2X.

Step 2: multiply the 2 with the 4 and get 8

Step 3: your answer is 2X+8

7 0
3 years ago
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