Answer:
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Answer:
maximum height is 4.058 metres
Time in air = 0.033 second
Step-by-step explanation:
Given that the equation height h
h = -212t^2 + 7t + 4
What is the toy's maximum height?
Let us assume that the equation is a perfect parabola
Time t at Maximum height will be
t = -b/2a
Where b = 7 and a = - 212
t = -7/ - 212 ×2
t = 7/ 424 = 0.0165s
Substitute t in the main equation
h = - 212(7/424)^2 + 7(7/424) + 4
h = - 0.05778 + 0.115567 + 4
h = 4.058 metres
Therefore the maximum height is 4.058 metres
How long is the toy in the air?
The object will go up and return to the ground.
At ground level, h = 0
-212t^2 + 7t + 4 = 0
212t^2 - 7t - 4 = 0
You can factorize the above equation and pick the positive time t since time can't be negative
Or
Since we have assumed that it's a perfect parabola,
Total time in air = (-b/2a) × 2
Time in air = 0.0165 × 2 = 0.033 s
Answer:
π/36 sec-1
Step-by-step explanation:
From the question we are given the formula below
s = rwt ..........eqn(1)
Where s= π/3m, r=3 m, t= 4 sec
We were not given value of " w" which implies we are required to find out values of" w"
We can make " w " the subject of the formula from eqn(1)
s = rwt
w= s/(rt)........eqn(2)
Then substitute for the values in eqn(2)
w= (π/3m ) / ( 3m × 4 sec)
= π/36 sec-1
Hence, the value of the
missing variable is π/36 sec-1
Answer:
small dogs= 5
large dogs= 3
Step-by-step explanation:
Step one:
given data
let the number of small dogs be x
and the number of large dogs be y
Ryan earns $5 for each small dog he walks and $8 for each large dog he walks.
He walked 8 dogs and made a total of $49
so
5x+8y=49----------1
x+y=8---------------2
x=8-y
5(8-y)+8y=49
40-5y+8y=49
collect like terms
3y= 49-40
3y=9
divide both sides by 3
y=9/3
y=3
put y= 3 in eqn 2
x+3=8
x=8-3
x=5
A, B, C are all more than -11 when divided by 3.
If you assume the question was phrased wrongly and they meant less than, then D is the answer.
Edit: seems like the question is incomplete, what is the number divided by?
