Question

Assume that a single page of printed text requires 52 lines of text, and that each line of text averaged 80 characters. If each character takes up two bytes of storage, how many bytes are required to hold a 500 page novel?

Answer 1

Answer:

4160000 bytes

Explanation:

One page = 52 lines of text

One line of text = 80 characters

=> One page = 80 x 52 = 4160 characters

Therefore, 500 pages of text will have 4160 x 500 characters = 2080000 characters.

Since 1 character takes up 2 bytes of computer memory, it impleies that a 500 page novel will take up 2080000 x 2 bytes = 4160000 bytes.