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marusya05 [52]
4 years ago
9

Assume that a single page of printed text requires 52 lines of text, and that each line of text averaged 80 characters. If each

character takes up two bytes of storage, how many bytes are required to hold a 500 page novel?
Computers and Technology
1 answer:
zysi [14]4 years ago
5 0

Answer:

4160000 bytes

Explanation:

One page = 52 lines of text

One line of text = 80 characters

=> One page = 80 x 52 = 4160 characters

Therefore, 500 pages of text will have 4160 x 500 characters = 2080000 characters.

Since 1 character takes up 2 bytes of computer memory, it impleies that a 500 page novel will take up 2080000 x 2 bytes = 4160000 bytes.

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Create a Boolean function odd_number_digits(n) that returns True when a positive integer has an odd number of digits. (You may a
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Answer:

Following are the code to this question:

import java.util.*;//import package for user input

public class Main//defining class main

{

   public static boolean odd_number_digits(int n)//defining boolean method odd_number_digits

   {

       if(n>0 && n%2!=0)//defining if block that check value is positive and odd number

       {

       return true;//return value true

       }

       else//defining else block

       {

           return false;//return false value

       }

   }

   public static void  sum_odd_digits(int n)//defining a method sum_odd_digits

   {

       int sum=0,i;//defining integer variable

       for(i=0;i<=n;i++)//defining for loop

       {

           if(i%2!=0)//defining if block for odd number

           {

               sum=sum+i;//add odd number

           }

       }

      System.out.print(sum);//use print method to print sum value

   }

public static void main(String[] args) //defining main method

   {

       Scanner ox=new Scanner(System.in);//creating Scanner object

       int n= ox.nextInt();//defining integer variable for input value

       System.out.print(odd_number_digits(n)+ "\n");//use print method to call method

       System.out.println("Sum of odd numbers: ");//print message

       sum_odd_digits(n);//calling method

   }

}

Output:

please find the attachment.

Explanation:

In the above code, two methods "odd_number_digits and sum_odd_digits" are defined in which the first method return type is boolean because it will true or false value, and the second method returns the sum of odd numbers.

In the "odd_number_digits" method,  an integer variable passes as an argument and inside the method, if block is used that check value is a positive and odd number then it will return a true value.

In the "sum_odd_digits" method, it accepts an integer parameter "n", and define integer variable "sum" inside the method, which uses the for loop, inside the loop if block is used that counts odd numbers and adds its in sum and print its value.

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