Answer:
a) r = 0.974
b) Critical value = 0.602
Step-by-step explanation:
Given - Two separate tests are designed to measure a student's ability to solve problems. Several students are randomly selected to take both test and the results are give below
Test A | 64 48 51 59 60 43 41 42 35 50 45
Test B | 91 68 80 92 91 67 65 67 56 78 71
To find - (a) What is the value of the linear coefficient r ?
(b) Assuming a 0.05 level of significance, what is the critical value ?
Proof -
A)
r = 0.974
B)
Critical Values for the Correlation Coefficient
n alpha = .05 alpha = .01
4 0.95 0.99
5 0.878 0.959
6 0.811 0.917
7 0.754 0.875
8 0.707 0.834
9 0.666 0.798
10 0.632 0.765
11 0.602 0.735
12 0.576 0.708
13 0.553 0.684
14 0.532 0.661
So,
Critical r = 0.602 for n = 11 and alpha = 0.05
The answer to this question is D) 13.9 in.
Try using the Pythagorean theorem when solving to get the hypotenuse or other angles for a right triangle.
I have attached a chart of the given information. Using subtraction from 100 and the other totals, you should be able to figure out the answer. If not, comment and I will send the completed chart
Answer:

Step-by-step explanation:
Using the formula for the exponential decay that is
, we have N=
,
and k=0.1374.
Thus,
becomes



Taking log on both sides, we get




Answer:
The leading term is 2x^7. Since n is odd and a is positive, the end behavior is down and up.