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wel
4 years ago
9

brett has been studying a type of bacteria that doubles every month. Originally, there were 5 bacterial cells. He wants to know

how many there will be after 42 months?
Mathematics
2 answers:
Sedbober [7]4 years ago
8 0

Answer:

Step-by-step explanation:

Originally, there were only five bacterial cells. After one month, the amount of bacteria is doubled with ten bacteria. The growth is represented by the formula:

a42 = 5 x 2^1

After 42 months, the growth can be solved using this formula:

a42 = 5 x 2^42 just so you know my cuz help me shes good in this

igor_vitrenko [27]4 years ago
4 0

Answer:

N=2.1990232556 \times 10^{13}

Step-by-step explanation:

Given : Brett has been studying a type of bacteria that doubles every month. Originally, there were 5 bacterial cells.

To Find: He wants to know how many there will be after 42 months?

Solution:

Since we are given that initially there were 5 bacterial cells.

Bacteria doubles every month

Let n denotes the number of months .

Function becomes : N=N_0(2)^n

N_0 = initial amount

N = amount after n months

So, N=5(2)^n

Substitute n = 42

N=5(2)^{42}

N=2.1990232556 \times 10^{13}

Thus there will be 2.1990232556 \times 10^{13} bacteria after 42 months.

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