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tankabanditka [31]
2 years ago
6

City A grows by 5% every year. In 2021, it has a population of 145,201. What will the population be in 2037?

Mathematics
2 answers:
BartSMP [9]2 years ago
5 0

Initial population=145,201

Total years=2037-2001=36

\\ \sf\longmapsto S=P\left(1+\dfrac{r}{100}\right)^t

\\ \sf\longmapsto S=145201\left(1+\dfrac{5}{100}\right)^{36}

\\ \sf\longmapsto S=145201\left(\dfrac{105}{100}\right)^{36}

\\ \sf\longmapsto S=145201(1.05)^{16}

\\ \sf\longmapsto S=145201(2.18)

\\ \sf\longmapsto S\approx 316955

Done

Diano4ka-milaya [45]2 years ago
4 0

Answer:

About 316,955 people

Step-by-step explanation:

The population of this city can be modeled with the formula P=I\cdot(1.05^t), where P represents the current population, I represents the initial population, and t represents the amount of time in years since the start of the model. Plugging in 145,201 for I and (2037-2021)=16 for t, we get:

P=145201\cdot(1.05)^{16}\approx145201\cdot2.18\approx 316955

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Suppose a large shipment of laser printers contained 18% defectives. If a sample of size 340 is selected, what is the probabilit
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Answer:

The probability that the sample proportion will be greater than 13% is 0.99693.

Step-by-step explanation:

We are given that a large shipment of laser printers contained 18% defectives. A sample of size 340 is selected.

Let \hat p = <u><em>the sample proportion of defectives</em></u>.

The z-score probability distribution for the sample proportion is given by;

                         Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  }  ~ N(0,1)

where, p = population proportion of defective laser printers = 18%

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Now, the probability that the sample proportion will be greater than 13% is given by = P(\hat p > 0.13)

         P(\hat p > 0.13) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  } > \frac{0.13-0.18}{\sqrt{\frac{0.13(1-0.13)}{340}}  } ) = P(Z > -2.74) = P(Z < 2.74)

                                                                      = <u>0.99693</u>

The above probability is calculated by looking at the value of x = 2.74 in the  table which has an area of 0.99693.

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