Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:
Compute the sample size as follows:
![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)
Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Answer:
Right of -7 and left of -1
Step-by-step explanation:
-7 is in the left and -4 is in the right
-7<4
-4 in the left and -1 in the right
-4<-1
just use directions
Answer:
3.74 x 10^5
Step-by-step explanation:
First expand the term in scientific notation into normal notation.
3.3 x 10^5 - Here the ^5 tells us to move the decimal five places to the right, so we go from
3.30000 to
330000.00
So 3.3 x 10^5 = 330,000
Now add that to 44,000 and you get 374,000.
Return this number to scientific notation. Move the decimal back to its spot before the 3. We go from
374,000.00 to
3.74000
Once again the decimal has moved five places, so that is the number in the exponent of the our scientific notation, and therefore our answer is
3.74 x 10^5
The slope of the line is -4
Answer: 3.83
Step-by-step explanation:
(2.24)(1.71)
=3.83
I think you just simply solve it
