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Zolol [24]
3 years ago
7

Mr. Gonzalez bought 5 pounds of grapes for $15.How much did he spend per pound?

Mathematics
1 answer:
egoroff_w [7]3 years ago
7 0
15 : 5 = 3$


Total cost : quantity = single cost



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C and d please help me im stuck i promise i will give a thank
Troyanec [42]

Answer:

attach the graph in orfer for us to answer

Step-by-step explanation:

3 0
3 years ago
What is the solution to –4|–2x + 6| = –24?
Oduvanchick [21]
What is the solution to –4|–2x + 6| = –24?

-4║-2x+6║=-24
-4/-4║-2x+6║=-24/-4 division property
║-2x+6║=6 simplified

Positive Negative
-2x+6=6 -2x+6=-6
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8 0
3 years ago
Evaluate the function f(x) at the given numbers (correct to six decimal places). F(x) = x2 − 5x x2 − x − 20 , x = 5.5, 5.1, 5.05
exis [7]

we are given

f(x)=\frac{x^2-5x}{x^2-x-20}

Firstly, we will simplify it

f(x)=\frac{x(x-5)}{(x-5)(x+4)}

f(x)=\frac{x}{(x+4)}

At x=5.5:

we can plug x=5.5

f(5.5)=\frac{5.5}{(5.5+4)}

f(5.5)=0.578947

At x=5.1:

we can plug x=5.1

f(5.1)=\frac{5.1}{(5.1+4)}

f(5.1)=0.56043956

At x=5.05:

we can plug x=5.05

f(5.05)=\frac{5.05}{(5.05+4)}

f(5.05)=0.558011

At x=5.01:

we can plug x=5.01

f(5.01)=\frac{5.01}{(5.01+4)}

f(5.01)=0.5560488

At x=5.005:

we can plug x=5.005

f(5.005)=\frac{5.005}{(5.005+4)}

f(5.005)=0.5558023

At x=5.001:

we can plug x=5.001

f(5.001)=\frac{5.001}{(5.001+4)}

f(5.001)=0.5556049

At x=4.9:

we can plug x=4.9

f(4.9)=\frac{4.9}{(4.9+4)}

f(4.9)=0.5505617

At x=4.95:

we can plug x=4.95

f(4.95)=\frac{4.95}{(4.95+4)}

f(4.95)=0.5530726

At x=4.99:

we can plug x=4.99

f(4.99)=\frac{4.99}{(4.99+4)}

f(4.99)=0.55506117

At x=4.995:

we can plug x=4.995

f(4.995)=\frac{4.995}{(4.995+4)}

f(4.995)=0.55503085

At x=4.999:

we can plug x=4.999

f(4.999)=\frac{4.999}{(4.999+4)}

f(4.999)=0.55550616



7 0
3 years ago
What is the answer to 8.(x.4)​
RSB [31]

Answer:

32x

Step-by-step explanation:

3 0
3 years ago
70 points<br> Need answer fast
Marysya12 [62]
I would say C.

-if 77 is 16.5 then i would guess a 75 gram plant would put off not much less
4 0
3 years ago
Read 2 more answers
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