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Alecsey [184]
3 years ago
15

The answer I need this answer emergency pls help

Mathematics
1 answer:
HACTEHA [7]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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George is helping the manager of the local produce market expand her business by distributing flyers
spin [16.1K]

Answer:

20 + 0.05x ≥ 65

Step-by-step explanation:

20 is by itself since thats what he earns extra per day.

Since he earns 0.05 per flyer, that means we are going to need a variable since we don't know how many flyers he passes. Let x be equal to that.

Since he wants to make at LEAST 65 we are going to use the greater than or equal to symbol since he doesn't want to make less than that.

20 + 0.05x ≥ 65

Best of Luck!

4 0
3 years ago
How much interest is earned in 2 years on an investment of $2000? The interest rate is 3%.
Lelechka [254]

 In this sum we will calculate using the simple  interest.


Simple interest is calculated from the formula :

I  = PRT

where I is the interest, P is the principal, R is interest rate per year and t is time in years.

I = 2000 × 3 % x 2

We have to turn 3% to its decimal fraction which is 0.03, so:

I = 2000 × 0.03 × 2

I = 60 ×  2

I = 120

Therefore the interest earned in two years will amount to 120 $


7 0
3 years ago
Can anyone help me on this problem, please? It's from a section on literal equations.
Agata [3.3K]
If he charges $145 he worked for 5 hours at $20 an hour
4 0
2 years ago
Read 2 more answers
Paula can make 14 beaded bracelets in an hour.Tina can make 13 bracelets in an hour.In one week,Paula made bracelets for 6 hours
Leno4ka [110]
Paula would be 14 times 6 or 84
Tina would be 13 times 8 or 104
So tina made more
4 0
2 years ago
Two streams flow into a reservoir. Let X and Y be two continuous random variables representing the flow of each stream with join
zlopas [31]

Answer:

c = 0.165

Step-by-step explanation:

Given:

f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3,

f(x, y) = 0 otherwise.

Required:

The value of c

To find the value of c, we make use of the property of a joint probability distribution function which states that

\int\limits^a_b \int\limits^a_b {f(x,y)} \, dy \, dx  = 1

where a and b represent -infinity to +infinity (in other words, the bound of the distribution)

By substituting cx y(1 + y) for f(x, y)  and replacing a and b with their respective values, we have

\int\limits^3_0 \int\limits^3_0 {cxy(1+y)} \, dy \, dx  = 1

Since c is a constant, we can bring it out of the integral sign; to give us

c\int\limits^3_0 \int\limits^3_0 {xy(1+y)} \, dy \, dx  = 1

Open the bracket

c\int\limits^3_0 \int\limits^3_0 {xy+xy^{2} } \, dy \, dx  = 1

Integrate with respect to y

c\int\limits^3_0 {\frac{xy^{2}}{2}  +\frac{xy^{3}}{3} } \, dx (0,3}) = 1

Substitute 0 and 3 for y

c\int\limits^3_0 {(\frac{x* 3^{2}}{2}  +\frac{x * 3^{3}}{3} ) - (\frac{x* 0^{2}}{2}  +\frac{x * 0^{3}}{3})} \, dx = 1

c\int\limits^3_0 {(\frac{x* 9}{2}  +\frac{x * 27}{3} ) - (0  +0) \, dx = 1

c\int\limits^3_0 {(\frac{9x}{2}  +\frac{27x}{3} )  \, dx = 1

Add fraction

c\int\limits^3_0 {(\frac{27x + 54x}{6})  \, dx = 1

c\int\limits^3_0 {\frac{81x}{6}  \, dx = 1

Rewrite;

c\int\limits^3_0 (81x * \frac{1}{6})  \, dx = 1

The \frac{1}{6} is a constant, so it can be removed from the integral sign to give

c * \frac{1}{6}\int\limits^3_0 (81x )  \, dx = 1

\frac{c}{6}\int\limits^3_0 (81x )  \, dx = 1

Integrate with respect to x

\frac{c}{6} *  \frac{81x^{2}}{2}   (0,3)  = 1

Substitute 0 and 3 for x

\frac{c}{6} *  \frac{81 * 3^{2} - 81 * 0^{2}}{2}    = 1

\frac{c}{6} *  \frac{81 * 9 - 0}{2}    = 1

\frac{c}{6} *  \frac{729}{2}    = 1

\frac{729c}{12}    = 1

Multiply both sides by \frac{12}{729}

c    =  \frac{12}{729}

c    =  0.0165 (Approximately)

8 0
3 years ago
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